Chapter 10: Problem 57
Give solutions over the interval \([0,2 \pi)\) as approximations to the nearest hundredth when exact values cannot be determined. You may need to use the quadratic formula. Give approximate answers in Exercises \(59-64\) to the nearest tenth of a degree over the interval \(\left[0^{\circ}, 360^{\circ}\right)\) $$2 \cos ^{2} x+2 \cos x=1$$
Short Answer
Step by step solution
Simplify the Equation
Use the Quadratic Formula
Solve the Discriminant
Solve for \( \cos x \)
Find Angles in Degree Measure
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
- A positive discriminant means two distinct real solutions.
- A zero discriminant results in one real repeated solution.
- A negative discriminant indicates no real solutions.
Cosine Function
- It is periodic with a period of \(2\pi\), meaning that \( \cos(x + 2\pi) = \cos x \).
- The range is from \(-1\) to \(1\), inclusive.
- It is even, so \( \cos(-x) = \cos x \).
Angle Approximation
- Ensure that the angle unit (degrees or radians) is correct as required.
- Be mindful of quadrant considerations, as functions like cosine have symmetry and periodic nature.
- Understand the tolerance of the approximation, acknowledging how close the result is to the exact value.