/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Use identities to write each exp... [FREE SOLUTION] | 91Ó°ÊÓ

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Use identities to write each expression as a function with \(x\) as the only argument. $$\sin \left(180^{\circ}-x\right)$$

Short Answer

Expert verified
\( \sin(180^{\circ} - x) = \sin(x) \).

Step by step solution

01

Identify the Trigonometric Identity

The expression \( \sin(180^{\circ} - x) \) involves an angle complementary to 180 degrees. We can use the trigonometric identity for sine that states: \( \sin(180^{\circ} - x) = \sin(\pi - x) = \sin(x) \). This identity is derived from the sine difference formula or the angle subtraction identity for sine, as sine is an odd function around the origin.
02

Apply the Identity

Using the identity from Step 1, we replace \( \sin(180^{\circ} - x) \) with \( \sin(x) \). This simplification is possible because sine of an angle and its supplementary angle (totaling to 180°) have equal sine values.
03

Conclusion

Having applied the identity, the expression \( \sin(180^{\circ} - x) \) simplifies directly to \( \sin(x) \). Hence, the expression does not change function type and remains a sine function only depending on \( x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sine Function
The sine function is a crucial concept in trigonometry, used to describe the ratio of the length of the opposite side to the hypotenuse in a right triangle. It is a periodic function that repeats its values in a predictable pattern. In the unit circle, the sine of an angle corresponds to the y-coordinate of the point where the terminal side of the angle intersects the circle. Some important properties of the sine function include:
  • It is an odd function, meaning that \( \sin(-x) = -\sin(x) \).
  • The sine function is periodic with a period of 360° or \( 2\pi \ ext{ radians} \).
  • The range of sine is between -1 and 1 for all angles.
This function is also represented graphically as a smooth, wave-like curve that oscillates, making it quite significant in the study of waves, sound, and other areas of physics.
Angle Subtraction Identity
The angle subtraction identity for sine is a formula that helps when dealing with the sine of an angle difference. This identity is: \\(\sin(A - B) = \sin(A) \cos(B) - \cos(A) \sin(B)\).\) It is particularly useful in simplifying expressions involving trigonometric functions, enabling calculations that otherwise might be complicated. In the case of \( \sin(180^{\circ} - x) \), we use a key property of the sine function: \( \sin(\pi - x) = \sin(x) \), where \( \pi = 180^{\circ} \). This identity is derived from the more general angle subtraction formula, but in this particular case, since \( \cos(\pi) = -1 \) and \( \sin(\pi) = 0 \), it simplifies significantly to \( \sin(x) \. This simplicity allows for easier computation and understanding when handling trigonometric expressions.
Supplementary Angles
Supplementary angles are two angles whose sum is 180°. A fascinating feature of trigonometric functions, especially sine, is how they behave with supplementary angles. For example, the sine of an angle is equal to the sine of its supplementary angle. This means if you have an angle \( A \), then its supplementary angle is \( 180^{\circ} - A \), and \( \sin(180^{\circ} - A) = \sin(A) \). This property is not only beautiful in its symmetry but also useful:
  • It simplifies complex trigonometric problems.
  • It helps to analyze wave functions.
  • It provides insight into geometric relationships involving circles and triangles.
Understanding the concept of supplementary angles deepens one’s grasp of trigonometry and its applications in both theoretical and practical problems.

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Most popular questions from this chapter

The equation \(\cot \frac{x}{2}-\csc \frac{x}{2}-1=0\) has solution set \(\varnothing\) over the interval \([0,2 \pi) .\) The solution set to the inequality cot \(\frac{x}{2}-\csc \frac{x}{2}-1>0\) over this interval is \(\varnothing .\) Does the graph of \(y=\cot \frac{x}{2}-\csc \frac{x}{2}-1\) lie above or below the \(x\) -axis over this interval?

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