/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Solve each equation for solution... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each equation for solutions over the interval \([0,2 \pi)\) by first solving for the trigonometric finction. Do not use a calculator. $$\tan x-\cot x=0$$

Short Answer

Expert verified
The solutions are \(x = \frac{\pi}{4}, \frac{5\pi}{4}, \frac{3\pi}{4}, \frac{7\pi}{4}\).

Step by step solution

01

Rewrite the Cotangent Function

Rewrite the equation \( \tan x - \cot x = 0 \) using the identity \( \cot x = \frac{1}{\tan x} \). This gives us the equation \( \tan x - \frac{1}{\tan x} = 0 \).
02

Clear the Fraction

Multiply every term in the equation \( \tan x - \frac{1}{\tan x} = 0 \) by \( \tan x \) to eliminate the fraction: \( \tan^2 x - 1 = 0 \).
03

Solve the Quadratic Equation

The equation \( \tan^2 x - 1 = 0 \) is quadratic in form. Factor it into \((\tan x - 1)(\tan x + 1) = 0 \). This gives us two possible equations: \( \tan x - 1 = 0 \) and \( \tan x + 1 = 0 \).
04

Solve for \( \tan x = 1 \)

Solve \( \tan x = 1 \). The solutions are \( x = \frac{\pi}{4} \) and \( x = \frac{5\pi}{4} \) because tangent is positive in the first and third quadrants.
05

Solve for \( \tan x = -1 \)

Solve \( \tan x = -1 \). The solutions are \( x = \frac{3\pi}{4} \) and \( x = \frac{7\pi}{4} \) because tangent is negative in the second and fourth quadrants.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
The tangent function, denoted as \( \tan x \), is a fundamental trigonometric function that relates the angle of a right triangle to the ratios of two of its sides. Specifically, in a right triangle, the tangent of angle \( x \) is defined as the ratio of the length of the opposite side to the length of the adjacent side. For any angle \( x \), the tangent function can be expressed as:
  • \( \tan x = \frac{\sin x}{\cos x} \)
This definition highlights two important aspects of the tangent function:
  • It is periodic, with a period of \( \pi \), which means the pattern of the function repeats every \( \pi \) units.
  • It is undefined when \( \cos x = 0 \) (i.e., \( x = \frac{\pi}{2}, \frac{3\pi}{2}, \ldots \) ), causing vertical asymptotes at these points.
The tangent function is crucial when solving equations like \( \tan x = 1 \) or \( \tan x = -1 \), as these equations help determine specific angles at which the ratios equal 1 or -1. Solutions are typically found within specified intervals, such as \( [0, 2\pi) \), accounting for all possible angles that satisfy the equation within a complete cycle of the unit circle.
Cotangent Function
The cotangent function, symbolized as \( \cot x \), is the reciprocal of the tangent function. This means that for any angle \( x \), the cotangent is the ratio of the adjacent side to the opposite side in a right triangle. Mathematically, it is defined as:
  • \( \cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x} \)
The cotangent function has some distinctive characteristics:
  • It is periodic with a period of \( \pi \), similar to the tangent function.
  • It is undefined at points where \( \sin x = 0 \) (i.e., \( x = 0, \pi, 2\pi, \ldots \) ), resulting in vertical asymptotes at these angles.
When solving trigonometric equations involving cotangent, such as \( \tan x - \cot x = 0 \), it's essential to recognize the roles both tangent and cotangent play as reciprocal functions. Substituting \( \cot x = \frac{1}{\tan x} \) often facilitates the equation's simplification, making it easier to solve by transforming the expression into a quadratic form.
Quadratic Equations
Quadratic equations are polynomial equations of the second degree, commonly taking the form \( ax^2 + bx + c = 0 \). In the context of trigonometric equations, such as \( \tan^2 x - 1 = 0 \), they appear once we clear fractions or simplify expressions involving trigonometric identities. Breaking down a trigonometric equation into a quadratic form involves:
  • Transforming terms using identities, such as \( \cot x = \frac{1}{\tan x} \).
  • Eliminating fractions by multiplying through by denominators.
  • Commanding algebraic techniques to factor and solve for roots.
To solve \( \tan^2 x - 1 = 0 \), we derive:
  • Factor into \( (\tan x - 1)(\tan x + 1) = 0 \).
  • Set each factor to zero: \( \tan x - 1 = 0 \) and \( \tan x + 1 = 0 \).
  • Solve these to find \( x \) values that satisfy each equation within the interval \([0, 2\pi)\).
Understanding quadratic equations strengthens your ability to solve a wide array of mathematical problems, including those involving trigonometric functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Verify that each equation is an identity by using any of the identities introduced in the first three sections of this chapter. $$\frac{1}{\sec t-1}+\frac{1}{\sec t+1}=2 \cot t \csc t$$

Suppose you are solving a trigonometric equation to find solutions in \(\left[0^{\circ}, 360^{\circ}\right)\) and your work leads to $$ \frac{1}{3} \theta=45^{\circ}, 60^{\circ}, 75^{\circ}, 90^{\circ} $$ What are the corresponding values of \(\theta ?\)

Solve each problem. Suppose an airplane flying faster than sound goes directly over you. Assume that the plane is flying at a constant altitude. At the instant you feel the sonic boom from the plane, the angle of elevation to the plane is $$\alpha=2 \arcsin \frac{1}{m}$$ where \(m\) is the Mach number of the plane's speed. (The Mach number is the ratio of the speed of the plane to the speed of sound.) Find \(\alpha\) to the nearest degree for each value of \(m\) (a) \(m=1.2\) (b) \(m=1.5\) (c) \(m=2\) (d) \(m=2.5\)

Solve each equation over the interval \([0,2 \pi)\) $$\sin ^{2} \frac{x}{2}-1=0$$

Voltage of a Circuit When the two voltages $$V_{1}=30 \sin 120 \pi t$$ and $$V_{2}=40 \cos 120 \pi t$$are applied to the same circuit, the resulting voltage \(V\) will equal their sum. (Source: Bell, D., Fundamentals of Electric Circuits, Second Edition, Reston Publishing Company.) (a) Graph \(V=V_{1}+V_{2}\) over the interval \(0 \leq t \leq 0.05\) (b) Use the graph to estimate values for \(a\) and \(\phi\) so that \(V=a \sin (120 \pi t+\phi)\) (c) Use identities to verify that your expression for \(V\) is valid.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.