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Verify that each equation is an identity by using any of the identities introduced in the first three sections of this chapter. $$\frac{\cos ^{4} x-\sin ^{4} x}{\cos ^{2} x}=1-\tan ^{2} x$$

Short Answer

Expert verified
The identity is valid as both sides simplify to \( 1 - \tan^2 x \).

Step by step solution

01

Recognize a Difference of Squares

The numerator of the left-hand side of the equation, \( \cos^4 x - \sin^4 x \), can be rewritten using the difference of squares formula \( a^2 - b^2 = (a-b)(a+b) \). In this case, set \( a = \cos^2 x \) and \( b = \sin^2 x \). Hence, \( \cos^4 x - \sin^4 x = (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) \).
02

Simplify Using the Pythagorean Identity

Now, apply the Pythagorean identity \( \cos^2 x + \sin^2 x = 1 \) to simplify the expression. Therefore, \((\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) = (\cos^2 x - \sin^2 x) \) because \( \cos^2 x + \sin^2 x = 1 \).
03

Substitute into the Original Equation

Substitute the simplified expression for \(\cos^4 x - \sin^4 x\) into the original identity: \(\frac{\cos^2 x - \sin^2 x}{\cos^2 x} \).
04

Further Simplify

Simplify \( \frac{\cos^2 x - \sin^2 x}{\cos^2 x} \) by separating the fraction: \( \frac{\cos^2 x}{\cos^2 x} - \frac{\sin^2 x}{\cos^2 x} = 1 - \tan^2 x \), where \( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} \).
05

Verify Both Sides Equal

Now, observe that the left-hand side simplifies to exactly \( 1 - \tan^2 x \), which matches the right-hand side of the original identity, confirming the identity is valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
Understanding the difference of squares is essential in algebra. It is a simple yet powerful formula: \(a^2 - b^2 = (a-b)(a+b)\). This means any difference between two squares can be factored into a product of two binomials. In the exercise, \(\cos^4 x - \sin^4 x\) is expressed as a difference of squares. We identify \(a = \cos^2 x\) and \(b = \sin^2 x\), allowing us to rewrite the expression as \((\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x)\). Factoring this way makes the expression much simpler to work with. Recognizing such patterns is key in solving complex algebraic identities and can serve as a helpful tool in trigonometry.
Pythagorean Identity
The Pythagorean identity is a fundamental trigonometric identity that states \(\cos^2 x + \sin^2 x = 1\). It is derived from the Pythagorean theorem and is used extensively across various branches of math and physics. In our exercise, after applying the difference of squares, we can replace \(\cos^2 x + \sin^2 x\) with 1. This significantly simplifies the expression. By substituting 1 for \(\cos^2 x + \sin^2 x\), the original complex-looking fraction \((\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x)\) reduces to \(\cos^2 x - \sin^2 x\). This identity simplifies expressions and helps easily transition between different forms of trigonometric equations. Memorizing and understanding it is crucial for solving trigonometric identities and proofs.
Simplification Techniques
Simplification techniques in mathematics are methods used to make expressions easier to work with by reducing their complexity. Breaking down expressions allows us to see connections and relationships more clearly.In this exercise, once we applied the difference of squares and the Pythagorean identity, we simplified the fraction: \(\frac{\cos^2 x - \sin^2 x}{\cos^2 x}\). By dividing each term of the numerator by the denominator separately, we break it down into simpler fractions: \(\frac{\cos^2 x}{\cos^2 x} - \frac{\sin^2 x}{\cos^2 x}\).
  • The term \(\frac{\cos^2 x}{\cos^2 x}\) simplifies to 1.
  • The term \(\frac{\sin^2 x}{\cos^2 x}\) simplifies to \(\tan^2 x\), because \(\tan x = \frac{\sin x}{\cos x}\).
Combining these results gives us \(1 - \tan^2 x\), exactly matching the right side of the equation. Simplification not only confirms the identity but also makes intricate equations more manageable.

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Most popular questions from this chapter

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Solve each problem. Ear Pressure from a Pure Tone A pure tone has a constant frequency and amplitude, and it sounds rather dull and uninteresting. The pressures caused by pure tones on the eardrum are sinusoidal. The change in pressure \(P\) in pounds per square foot on a person's eardrum from a pure tone at time \(t\) in seconds can be modeled by the equation $$ P=A \sin (2 \pi f t+\phi) $$ where \(f\) is the frequency in cycles per second and \(\phi\) is the phase angle. When \(P\) is positive, there is an increase in pressure and the eardrum is pushed inward; when \(P\) is negative, there is a decrease in pressure and the eardrum is pushed outward. (a) Middle C has frequency 261.63 cycles per second. Graph this tone with \(A=0.004\) and \(\phi=\frac{\pi}{7}\) in the window \([0,0.005]\) by \([-0.005,0.005]\) (b) Determine analytically the values of \(t\) for which \(P=0\) on \([0,0.005],\) and support your answers graphically. (c) Determine graphically when \(P<0\) on \([0,0.005]\) (d) Would an eardrum hearing this tone be vibrating outward or inward when \(P<0 ?\)

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