Chapter 1: Problem 83
Solve each inequality analytically, writing the solution set in interval notation. Support your answer graphically. (Hint: Once part (a) is done, the answer to part (b) follows.) (a) \(9-(x+1)<0\) (b) \(9-(x+1) \geq 0\)
Short Answer
Expert verified
(a) \(x > 8\) is \((8, \infty)\); (b) \(x \leq 8\) is \((-
fty, 8]\).
Step by step solution
01
Simplify the Inequality (Part a)
Start with the given inequality: \(9 - (x + 1) < 0\). Simplify by distributing the negative sign: \(9 - x - 1 < 0\). This simplifies to \(-x + 8 < 0\).
02
Solve for x (Part a)
From \(-x + 8 < 0\), subtract 8 from both sides to get \(-x < -8\). Then, multiply both sides by -1, remembering to flip the inequality sign: \(x > 8\).
03
Write the Solution in Interval Notation (Part a)
The solution \(x > 8\) in interval notation is \((8, \infty)\).
04
Simplify the Inequality (Part b)
Start with the given inequality: \(9 - (x + 1) \geq 0\). Simplify by distributing the negative sign: \(9 - x - 1 \geq 0\). This simplifies to \(-x + 8 \geq 0\).
05
Solve for x (Part b)
From \(-x + 8 \geq 0\), subtract 8 from both sides to get \(-x \geq -8\). Then, multiply both sides by -1, remembering to flip the inequality sign: \(x \leq 8\).
06
Write the Solution in Interval Notation (Part b)
The solution \(x \leq 8\) in interval notation is \((-fty, 8]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a way of representing a set of numbers between two endpoints on the number line. It is a concise method to express inequalities and is particularly useful when the solutions involve ranges. The endpoints are included or excluded using brackets:
For part (b), where the solution was all numbers less than or equal to 8, the interval notation is \((-\infty, 8]\). The square bracket at 8 includes 8 in the solution set.
- Round brackets, like ")" and "(", indicate that the endpoint is not included in the set (also known as an "open interval").
- Square brackets, like "]" and "[", signify that the endpoint is included (known as a "closed interval").
For part (b), where the solution was all numbers less than or equal to 8, the interval notation is \((-\infty, 8]\). The square bracket at 8 includes 8 in the solution set.
Solution Sets
A solution set is the collection of all possible solutions that satisfy a given inequality or equation. It represents all the valid values of a variable that make the inequality true. For example, in this exercise,
- For inequality \(9 - (x + 1) < 0\), the solution set is the set of all real numbers greater than 8, which we expressed in the solution format as \(x > 8\).
- For inequality \(9 - (x + 1) \geq 0\), the solution set includes all real numbers less than or equal to 8, expressed as \(x \leq 8\).
Graphical Solution
A graphical solution to an inequality involves drawing the solution set on a number line. This visual representation helps in easily understanding the range of solutions and whether or not certain values are included.
For the solutions in our exercise:
For the solutions in our exercise:
- For the inequality \(x > 8\), we would draw an open circle at 8 and shade the line extending to the right towards infinity. This illustrates that the numbers are greater than 8 but do not include 8 itself.
- For \(x \leq 8\), a filled-in circle at 8 indicates that 8 is part of the solution set, with shading to the left towards negative infinity, showing the values are 8 and below.
Analytical Methods
Analytical methods involve using algebraic manipulation to solve inequalities or equations precisely. In solving inequalities, we follow a systematic approach similar to solving equations but with special care regarding the inequality sign.
Here is a brief overview of this approach as used in the given exercise:
Here is a brief overview of this approach as used in the given exercise:
- We began by simplifying the inequalities \(9 - (x + 1) < 0\) and \(9 - (x + 1) \geq 0\) to \(-x + 8 < 0\) and \(-x + 8 \geq 0\), respectively, by distributing the negative sign and simplifying the expression.
- Next, we isolated the variable \(x\) by performing arithmetic operations. We subtracted 8 from both sides, followed by multiplying through by -1. It is important to remember that multiplying or dividing both sides of an inequality by a negative number reverses the inequality sign.
- Finally, this led to solutions \(x > 8\) and \(x \leq 8\), giving us the full range of solutions for both inequalities.