/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Graph each hyberbola by hand. Gi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$144 x^{2}-49 y^{2}=7056$$

Short Answer

Expert verified
Vertices: (-7,0) and (7,0); Domain: \(x \leq -7\) or \(x \geq 7\); Range: \(y \in \mathbb{R}\).

Step by step solution

01

Standard Form of the Hyperbola

Start by writing the given equation of the hyperbola in its standard form. The equation is \(144 x^{2} - 49 y^{2} = 7056\). Divide every term by 7056 to simplify:\[\frac{144 x^{2}}{7056} - \frac{49 y^{2}}{7056} = 1\]. Simplifying, we get: \[ \frac{x^{2}}{49} - \frac{y^{2}}{144} = 1 \]. This resembles the standard form of a hyperbola centered at the origin, \(\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \).
02

Identify Parameters 'a' and 'b'

From the standard form \(\frac{x^{2}}{49} - \frac{y^{2}}{144} = 1\), identify that \(a^{2} = 49\) and \(b^{2} = 144\).Therefore, \(a = 7\) and \(b = 12\). These values determine the lengths of the semi-major and semi-minor axes of the hyperbola.
03

Find the Vertices and Asymptotes

Since this hyperbola opens horizontally (since \(x^{2}\) term is positive), the vertices are at \((a, 0) = (7, 0)\) and \((-a, 0) = (-7, 0)\). The equations of the asymptotes for a horizontal hyperbola are \(y = \pm \frac{b}{a}x\). So, the asymptotes are \(y = \pm \frac{12}{7}x\).
04

Graph the Hyperbola

Draw a coordinate system and plot the center at the origin (0, 0). Mark the vertices at (7, 0) and (-7, 0). Then, sketch the asymptotes through the center with the slope \(\pm \frac{12}{7}\). The branches of the hyperbola will approach these asymptotes but never touch them. Draw the hyperbola with the two branches opening horizontally, intersecting x-axis at the vertices.
05

Determine the Domain and Range

For a horizontally oriented hyperbola, the domain is all real numbers except the points between the vertices, determined by \(x \leq -7\) or \(x \geq 7\).The range is all real numbers, so \(y \in \mathbb{R}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Form of Hyperbola
The standard form of a hyperbola is a mathematical expression that makes it easy to understand key features of the hyperbola, such as its orientation and dimensions. A hyperbola can open either horizontally or vertically, and its standard form reflects this orientation.

For a hyperbola that opens horizontally, the standard form is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]
For those that open vertically, it switches to:\[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \]

In our given example, we transformed the equation \(144 x^{2} - 49 y^{2} = 7056\) into its standard form:\[ \frac{x^2}{49} - \frac{y^2}{144} = 1 \]
This tells us that the hyperbola is horizontal because the \(x^2\) term comes first.

By simplifying the coefficients, this form also allows us to identify the semi-major axis (\(a\)) and semi-minor axis (\(b\)). Here, \(a = 7\) and \(b = 12\), which are essential for graphing and understanding the hyperbola's shape and dimensions.
Asymptotes
Asymptotes in a hyperbola are straight lines that the curve approaches but never actually intersects. They give the hyperbola its distinctive shape, guiding the curvature of the hyperbolic branches. Understanding asymptotes is crucial when sketching hyperbolas.

For a horizontal hyperbola like \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), the equations for the asymptotes are:\[ y = \pm \frac{b}{a}x \]
This represents two diagonal lines crossing the center of the hyperbola.

In our case, with \(a = 7\) and \(b = 12\), these asymptotes are:\[ y = \pm \frac{12}{7}x \]
These lines will never be touched by the hyperbola's arms, yet they are key in shaping its direction and the width of each opening. Plotting these lines makes it easier to sketch the hyperbola by providing a visual guide for how it curves.
Domain and Range
The domain and range of a hyperbola describe the allowable values of \(x\) and \(y\) that the hyperbola can take. This helps define the extent of the hyperbola on a coordinate plane.

- **Domain**: For a horizontal hyperbola, the domain is typically all real numbers except for a limited interval between the vertices. It can be expressed as: \[ x \leq -a \text{ or } x \geq a \]
In our example, because the vertices are located at \((-7, 0)\) and \((7, 0)\), the domain is: \[ x \leq -7 \text{ or } x \geq 7 \]
- **Range**: The range encompasses all real numbers since the arms of the hyperbola extend infinitely in the vertical direction. Thus, for our hyperbola: \[ y \in \mathbb{R} \]
Understanding the domain and range helps complete the mental map of the hyperbola's shape and the space it occupies on a plane.
Vertices of Hyperbola
The vertices of a hyperbola are critical points that represent where the hyperbola is closest to its center. These points lie on the main axis and help define the shape and location of the hyperbola.

For a horizontal hyperbola, the vertices are found along the x-axis, at points \( (a, 0) \) and \( (-a, 0) \). In the formula \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), \(a\) determines the distance to each vertex from the center.

In our example, with \(a = 7\), the vertices are:\[ (7, 0) \text{ and } (-7, 0) \]

These are the points where the hyperbola intersects its axis of symmetry, marking the path of its nearest approach. Knowing the vertices assists in sketching the correct shape and size of the hyperbola on a graph.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Path of an Object on a Planet When an object moves under the influence of a gravitational force (without air resistance), its path can be parabolic. This is the path of a ball thrown near the surface of a planet or other celestial object. Suppose two balls are simultaneously thrown upward at a \(45^{\circ}\) angle on two different planets. If their initial velocities are both \(30 \mathrm{mph}\), then their \(x y\) -coordinates in feet can be expressed by the equation $$ y=x-\frac{g}{1922} x^{2} $$ where \(g\) is the acceleration due to gravity. The value of \(g\) will vary with the mass and size of the planet. (Source: Zeilik, M., S. Gregory, and E. Smith, Introductory Astronomy and Astrophysics, Saunders College Publishers.) (a) On Earth, \(g=32.2\) and on Mars, \(g=12.6 .\) Find the two equations, and use the same screen of a graphing calculator to graph the paths of the two balls thrown on Earth and Mars. Use the window [0,180] by \([0,120] .\) (Hint: If possible, set the mode on your graphing calculator to simultaneous.) (b) Determine the difference in the horizontal distances traveled by the two balls.

Find an equation for each hyperbola. \(x\) -intercepts ( \(\pm 3,0\) ); foci ( \(\pm 4,0\) )

Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=(y-4)^{2}+2$$

Solve each problem. The Roman Colosseum is an ellipse with major axis 620 feet and minor axis 513 feet. Approximate the distance between the foci of this ellipse.

For individual or group investigation. Consider the ellipse and hyperbola defined by $$\frac{x^{2}}{16}+\frac{y^{2}}{12}=1 \quad \text { and } \quad \frac{x^{2}}{4}-\frac{y^{2}}{12}=1$$ respectively. Graph the ellipse with your calculator, and trace to find the coordinates of several points on the ellipse.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.