Chapter 7: Problem 33
Graph each circle by hand if possible. Give the domain and range. $$(x-2)^{2}+y^{2}=36$$
Short Answer
Expert verified
Center: (2,0), Radius: 6. Domain: [-4,8]. Range: [-6,6].
Step by step solution
01
Recognize the Equation Format
The given equation \((x-2)^{2} + y^{2} = 36\) is in the standard form \((x-h)^2 + (y-k)^2 = r^2\), which represents a circle. Here, \((h,k)\) is the center of the circle and \(r\) is the radius.
02
Identify the Center of the Circle
From the equation, \((x-2)^2 + y^2 = 36\), we identify the center of the circle as \((h,k) = (2,0)\). This is because the term \((x-2)\) indicates a horizontal shift of 2 units to the right, while there is no vertical shift, so \(k = 0\).
03
Determine the Radius of the Circle
The equation shows \(36\) on the right side, which is equal to \(r^2\). Thus, the radius \(r\) is the square root of 36. Therefore, \(r = \sqrt{36} = 6\).
04
Graph the Circle
To graph the circle, plot the center at \((2,0)\) on the coordinate plane, then draw a circle with a radius of 6. This means the circle extends 6 units in all directions from the center: right to \((8,0)\), left to \((-4,0)\), up to \((2,6)\), and down to \((2,-6)\).
05
Find the Domain
The domain of the circle is the set of all possible \(x\)-values. Since the circle extends horizontally from \(x = -4\) to \(x = 8\), the domain is \([-4,8]\).
06
Find the Range
The range of the circle is the set of all possible \(y\)-values. The circle extends vertically from \(y = -6\) to \(y = 6\), so the range is \([-6,6]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain and Range
When discussing the domain and range of a circle on a graph, we are essentially talking about the smallest and largest values that the circle reaches along the x-axis and y-axis. The **domain** refers to all the possible x-values that are part of the circle. For our circle, the domain is from
(2, 0) to the left and 6 units to the right.
The **range** is similar but pertains to the y-values. It tells us the vertical span of the circle on the graph. The range extends from the lowest y-value to the highest:
- -4 to 8
- Represented as
(2, 0) to the left and 6 units to the right.
The **range** is similar but pertains to the y-values. It tells us the vertical span of the circle on the graph. The range extends from the lowest y-value to the highest:
- -6 to 6
- Expressed as
- Look at how far the circle reaches horizontally and vertically.
- The domain is about the x-axis,
- The range about the y-axis.
Circle Equations
Circle equations typically come in the form of
For example, the equation \((x-2)^2 + y^2 = 36\) lets us know directly that the center of our circle is at point (2, 0). Why? The
- \((x-h)^2 + (y-k)^2 = r^2\), where:
- \((h, k)\) is the center of the circle.
- \(r\) is the radius.
For example, the equation \((x-2)^2 + y^2 = 36\) lets us know directly that the center of our circle is at point (2, 0). Why? The
- -x term,
- \((x-2)\), instructs us that the circle is shifted 2 units to the right, making the center's x-value 2.
- There is no shift in the y-direction since it's just
- \(y^2\). So, the y-coordinate of the center is 0.
- \(r^2 = 36\),
- thus \(r = \sqrt{36} = 6\).
Graphing Techniques
Graphing a circle is straightforward once you've deciphered its equation. Here’s an easy method to follow:
You don't need a compass, but visualizing a smooth, round curve is essential. Some additional tips:
- Plot the center first. For our circle, that’s (2, 0).
- Next, use the radius to mark key points around the center.
- To the right: (8, 0)
- To the left: (-4, 0)
- Upwards: (2, 6)
- Downwards: (2, -6)
You don't need a compass, but visualizing a smooth, round curve is essential. Some additional tips:
- Ensure your graph's scale is consistent,
- so your circle appears perfectly round.
- Check your key points by ensuring they align with the radius and center.