/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 For each plane curve, use a grap... [FREE SOLUTION] | 91Ó°ÊÓ

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For each plane curve, use a graphing calculator to generate the curve over the interval for the parameter \(t\), in the window specified. Then, find a rectangular equation for the curve. \(x=t, y=\sqrt{4-t^{2}},\) for \(t\) in \([-2,2]\) window: \([-6,6]\) by \([-4,4]\)

Short Answer

Expert verified
The rectangular equation is \( y = \sqrt{4 - x^2} \).

Step by step solution

01

Graph the Parametric Equations

Using a graphing calculator, input the parametric equations with the interval for \( t \) ranging from \(-2\) to \(2\). Set the window to \([-6, 6]\) for the x-axis and \([-4, 4]\) for the y-axis. Observe that the graph forms a semicircle covering the positive half of the y-axis.
02

Express \( y \) in terms of \( x \)

Given \( x = t \) and \( y = \sqrt{4 - t^2} \), substitute \( t \) with \( x \). Now the equation for \( y \) becomes \( y = \sqrt{4 - x^2} \).
03

Verify the Conversion to Rectangular Form

The equation \( y = \sqrt{4 - x^2} \) can be verified by noting that it represents the top half of the circle with radius 2 centered at the origin, satisfying the given parameter range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, are essential in geometry and algebra. They help us uniquely identify the position of points in a two-dimensional plane using an ordered pair format \(x, y\). This system allows us to describe the location of any point by using the perpendicular distances from two perpendicular lines, usually denoted as the x-axis and the y-axis. For example, if a point is placed at \(2, 3\), it means it is located 2 units along the x-axis and 3 units along the y-axis.
Key elements of rectangular coordinates include:
  • The x-coordinate, or abscissa, represents the horizontal distance from the origin.
  • The y-coordinate, or ordinate, signifies the vertical distance from the origin.
These coordinates are extremely valuable when translating parametric equations to a more familiar form, allowing us to visualize and analyze geometric shapes easily.
Graphing Calculator
A graphing calculator is an invaluable tool for visualizing complex mathematical equations. By inputting parametric or algebraic equations, students can view their graphical representation in real-time. This process provides a more intuitive understanding of mathematical concepts beyond solely numerical or symbolic calculations.
For parametric equations, graphing calculators can:
  • Generate graphical displays over specified parameter ranges.
  • Allow manipulation of viewing windows for a more detailed analysis.
  • Enhance learning by offering dynamic and interactive exploration of functions.
In our exercise, using a graphing calculator helps in plotting the semicircle within the specified window, \([-6, 6]\) by \([-4, 4]\), while the parameter \(t\) is within \([-2, 2]\). This gives a concrete visual appearance of how different equations manifest as distinct geometric shapes.
Semicircle
When we talk about a semicircle, we refer to half of a circle formed by cutting the circle along its diameter. This particular study focuses on the top half of a circle. The equation derived, \y = \sqrt{4 - x^2}\, represents this top half when plotted on a graph.
Important properties include:
  • It has a radius, which in this exercise is 2, originating from the center of the circle.
  • The equation \(y = \sqrt{4 - x^2}\) indicates points from the positive side of the y-axis.
  • It accurately maps points\(x\) ranging from -2 to 2, showing existence only on the positive hemisphere of the curve.
Understanding this concept helps students grasp the idea of how parametric equations translate to precise geometric representations and can make drawing shapes like semicircles easier.
Plane Curve
A plane curve is simply a curve that lies completely within a given plane. This can include various shapes such as circles, ellipses, and other more complex configurations. Given a set of parametric equations, the resulting graphical depiction is always a plane curve since both x and y involve only two dimensions.
The plane curve drawn from the parametric equations \(x = t\) and \(y = \sqrt{4 - t^2}\) forms a semicircle across the specified range of the parameter \(t\).
Essential considerations while dealing with plane curves include:
  • Understanding the constraints and domain of the parameters involved.
  • Identifying significant points that affect the curve, like intersections.
  • Recognizing symmetry, as in the case of a semicircle which is symmetric across the y-axis.
Adding these facets to one's understanding aids in elucidating how different algebraic and parametric equations represent shapes in a consistent, two-dimensional framework.

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Most popular questions from this chapter

Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$(y+2)^{2}=x+1$$

Write the equation in standard form for a hyperbola centered at ( \(h, k\) ). Identify the center and vertices. \(y^{2}+4 y-x^{2}+2 x=6\)

Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$9 x^{2}-4 y^{2}=1$$

Solve each problem. Structure of an Atom In \(1911,\) Ernest Rutherford discovered the basic structure of the atom by "shooting" positively charged alpha particles with a speed of \(10^{7}\) meters per second at a piece of gold foil \(6 \times 10^{-7}\) meter thick. Only a small percentage of the alpha particles struck a gold nucleus head-on and were deflected directly back toward their source. The rest of the particles often followed a hyperbolic trajectory because they were repelled by positively charged gold nuclei. Thus, Rutherford proposed that the atom was composed of mostly empty space and a small, dense nucleus. The figure shows an alpha particle \(A\) initially approaching a gold nucleus \(N\) and being deflected at an angle \(\theta=90^{\circ}\) \(N\) is located at a focus of the hyperbola, and the trajectory of \(A\) passes through a vertex of the hyperbola. (a) Determine the equation of the trajectory of the alpha particle if \(d=5 \times 10^{-14}\) meter. (b) Approximate the minimum distance between the centers of the alpha particle and the gold nucleus. (GRAPH CAN'T COPY)

Find an equation of a parabola that satisfies the given conditions. Focus \((2,1) ;\) directrix \(x=-1\)

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