Chapter 5: Problem 94
Use the change-of-base rule to find an approximation for each logarithm. $$\log _{200} 175$$
Short Answer
Expert verified
\( \log_{200} 175 \approx 0.974 \)
Step by step solution
01
Understand the Change-of-Base Formula
The change-of-base formula allows us to rewrite a logarithm \(\log_b a\) using logarithms of any other base, commonly base 10 or base e. The formula is: \\[\log_b a = \frac{\log_c a}{\log_c b}\] \where \(c\) is the new base. For this example, we'll use base 10.
02
Apply the Change-of-Base Formula
We will rewrite \(\log_{200} 175\) using base 10: \\[\log_{200} 175 = \frac{\log_{10} 175}{\log_{10} 200}\] \This expression allows us to compute the logarithm using a calculator, which typically supports log base 10.
03
Calculate Each Logarithm
Use a calculator to compute \(\log_{10} 175\) and \(\log_{10} 200\): \- \(\log_{10} 175 \approx 2.2430\) \- \(\log_{10} 200 \approx 2.3010\)
04
Divide to Find the Approximation
Now divide the two results from Step 3 using the formula from Step 2: \\[\frac{\log_{10} 175}{\log_{10} 200} \approx \frac{2.2430}{2.3010} \approx 0.974\] \Thus, \(\log_{200} 175 \approx 0.974\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithms: Understanding the Basics
Logarithms are a fundamental concept in mathematics, especially in algebra and calculus. They help to simplify expressions involving exponents by turning them into manageable numbers. When you see a logarithm written as \( \log_b a \), it asks the question: "What power do we need to raise \( b \) to, in order to get \( a \)?"
For example, in \( \log_2 8 \), we are asking what power do we need to raise 2 to, in order to get 8. The answer is 3, because \( 2^3 = 8 \). This makes logarithms extremely useful for solving equations where the unknown is an exponent. They are built specifically to unravel those tricky exponent numbers.
In practical scenarios:
For example, in \( \log_2 8 \), we are asking what power do we need to raise 2 to, in order to get 8. The answer is 3, because \( 2^3 = 8 \). This makes logarithms extremely useful for solving equations where the unknown is an exponent. They are built specifically to unravel those tricky exponent numbers.
In practical scenarios:
- Logarithms are used in science, engineering, and finance to deal with data that span large ranges.
- They help in simplifying calculations, especially those involving exponential growth and decay.
Base Conversion: Making Calculations Easier
Base conversion in logarithms allows us to work with different bases easily. The core idea is to translate a logarithm in one base to another base, more commonly base 10, which is widely supported by calculators. This is where the change-of-base formula comes into play.
The formula is written as:\[ \log_b a = \frac{\log_c a}{\log_c b} \]where \( c \) is the new base, generally 10 or \( e \) (natural logarithm). This transformation simplifies calculations significantly.
For example, to transform \( \log_{200} 175 \) using base 10, we express it as:\[ \log_{200} 175 = \frac{\log_{10} 175}{\log_{10} 200} \]This re-expression allows you to easily calculate the logarithm using standard scientific calculators.
Why change base?
The formula is written as:\[ \log_b a = \frac{\log_c a}{\log_c b} \]where \( c \) is the new base, generally 10 or \( e \) (natural logarithm). This transformation simplifies calculations significantly.
For example, to transform \( \log_{200} 175 \) using base 10, we express it as:\[ \log_{200} 175 = \frac{\log_{10} 175}{\log_{10} 200} \]This re-expression allows you to easily calculate the logarithm using standard scientific calculators.
Why change base?
- It converts complex logarithmic expressions into simpler forms, especially when the calculator doesn’t support certain bases.
- It facilitates more straightforward numerical computation by using a base like 10, which is a standard on most calculators.
Calculator Usage: Computing Logarithms
Using a calculator to compute logarithms, especially after using the change-of-base formula, is a valuable skill. Modern scientific calculators have built-in functions for base 10 (common logarithms) and base \( e \) (natural logarithms).
Here's how you can use a calculator effectively for logarithms:
1. **Locate the Logarithm Functions:** Most scientific calculators have \( \log \) and \( \ln \) buttons.
2. **Input Values for Base 10 Logarithm:** To calculate \( \log_{10} 175 \), enter 175, then press the \( \log \) button. Similarly, do this for \( 200 \).
3. **Compute the Division:** Once you have both values, divide them to find your result using the change-of-base formula:
\[ \frac{\log_{10} 175}{\log_{10} 200} \approx \frac{2.2430}{2.3010} \approx 0.974 \]This process allows you to handle logarithms beyond the standard bases directly, making complex calculations more accessible.
Pro tips for calculator use:
Here's how you can use a calculator effectively for logarithms:
1. **Locate the Logarithm Functions:** Most scientific calculators have \( \log \) and \( \ln \) buttons.
2. **Input Values for Base 10 Logarithm:** To calculate \( \log_{10} 175 \), enter 175, then press the \( \log \) button. Similarly, do this for \( 200 \).
3. **Compute the Division:** Once you have both values, divide them to find your result using the change-of-base formula:
\[ \frac{\log_{10} 175}{\log_{10} 200} \approx \frac{2.2430}{2.3010} \approx 0.974 \]This process allows you to handle logarithms beyond the standard bases directly, making complex calculations more accessible.
Pro tips for calculator use:
- Clear previous calculations to avoid errors in subsequent steps.
- Double-check entries for numerical accuracy.
- Familiarize yourself with your calculator’s specific functions to increase efficiency.