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Using the restrictions on the functions in Exercises \(123-126,\) find a formula for \(f^{-1}\). $$f(x)=-x^{2}+4, \quad x \geq 0$$

Short Answer

Expert verified
The inverse function is \( f^{-1}(x) = \sqrt{4 - x} \) for \( 0 \leq x \leq 4 \).

Step by step solution

01

Understand the given function

The given function is \( f(x) = -x^2 + 4 \) and it has the restriction \( x \geq 0 \). This means the function is only defined for non-negative values of \( x \). Our goal is to find the inverse function \( f^{-1}(x) \).
02

Set the output as y

To find the inverse, we start by setting \( f(x) = y \). So we have: \[ y = -x^2 + 4 \] We need to solve this equation for \( x \) in terms of \( y \).
03

Rearrange to isolate the x-term

Rearrange the equation to isolate the term containing \( x \): \[ -x^2 = y - 4 \] Next, we multiply both sides by \(-1\) to make \( x^2 \) positive: \[ x^2 = 4 - y \]
04

Solve for x

Since \( x \geq 0 \), take the positive square root: \[ x = \sqrt{4 - y} \] This expression represents \( x \) in terms of \( y \).
05

Write the inverse function

Since \( x = \sqrt{4 - y} \), we swap \( x \) and \( y \) to get the inverse function. Thus, \[ f^{-1}(x) = \sqrt{4 - x} \] This is the formula for the inverse function, valid for \( 0 \leq x \leq 4 \) because \( 4 - x \geq 0 \) under the square root constraint.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
Quadratic functions are a major breed in the world of algebra. They take the form of \( f(x) = ax^2 + bx + c \), where \( a, b, \) and \( c \) are constants. A defining feature of these functions is the \( x^2 \) term, which gives them a characteristic parabolic shape when graphed. In this exercise, we encounter a specific type of quadratic function: \( f(x) = -x^2 + 4 \), which is a downward-opening parabola due to the negative sign in front of \( x^2 \).
The vertex form of a quadratic function is especially useful for understanding its graph. The function \( f(x) = -x^2 + 4 \) can be seen as being in vertex form, \( f(x) = a(x-h)^2 + k \), where \( (h, k) \) is the vertex of the parabola. Here, \( h = 0 \) and \( k = 4 \), indicating that the vertex is positioned at the point \( (0, 4) \).
Quadratic functions can be manipulated and transformed, which includes finding their inverses, if possible. However, due to their parabolic nature, quadratics inherently do not have inverses unless restricted. That's where function restrictions come into play.
Function Restrictions
Function restrictions narrow down the domain or range of a function, making complex problems more manageable. They are a necessary tool when dealing with inverse functions.
Why are they important? Well, not every function has an inverse that's a real function. Quadratic functions, like \( f(x) = -x^2 + 4 \), are not one-to-one throughout their entire domain. That means, if we don’t restrict them, we’ll face issues finding a legitimate inverse function.
In this exercise, we note a critical restriction: \( x \geq 0 \). This restriction ensures that the function remains one-to-one. By only considering the portion of the parabola where \( x \geq 0 \), we maintain the necessary constraints for the inverse to exist and also be a function.
  • This limitation allows us to "invert" our quadratic safely.
  • It also keeps us within the realms of real, non-negative values and practical mathematics.
In essence, function restrictions transform potentially chaotic calculations into a structured, solvable problem.
Solving Equations
Solving equations form the backbone of mathematical problem-solving. In finding an inverse, we solve for the original variable in terms of the other variable.
So, we start from \( y = -x^2 + 4 \) and aim to express \( x \) in terms of \( y \). The journey of solving these equations involves:
  • Rearranging: Move terms around so the desired variable, here \( x \), starts to "stand alone" on one side of the equation.
  • Isolating: Sometimes you multiply or divide terms to peel away layers around \( x \). Here, multiplying by \( -1 \) helps flip \( -x^2 \) to \( x^2 \).
  • Square Rooting: With \( x^2 = 4-y \) and \( x \geq 0 \), we take the square root to solve for \( x \), ensuring we respect the restriction by only considering the positive root: \( x = \sqrt{4 - y} \).
With the inverse function \( f^{-1}(x) = \sqrt{4 - x} \), solving equations for inverses becomes a systematic approach. This method not only makes the math simpler but also unlocks inverse functions in everyday quadratic scenarios.

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