/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Evaluate \(f(x)\) at the given \... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate \(f(x)\) at the given \(x\). Approximate each result to the nearest hundredth. $$f(x)=x^{-0.71}, \quad x=3.8$$

Short Answer

Expert verified
\( f(3.8) \approx 0.41 \)

Step by step solution

01

Substitute x into the function

In the given function, replace the variable \(x\) with the value 3.8 to evaluate the function: \[ f(3.8) = (3.8)^{-0.71} \]
02

Calculate the exponent

To solve \((3.8)^{-0.71}\), use a calculator to find the power of 3.8 raised to the exponent -0.71. Performing the calculation, we find that: \[ (3.8)^{-0.71} \approx 0.408 \]
03

Round to the nearest hundredth

Round the result obtained in the previous step to the nearest hundredth place. In this case, the third decimal place is 8, so we round up the second decimal place. Thus, we have:\[ 0.408 \approx 0.41 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Evaluation
When evaluating a function, our main goal is to find the output, or result, of the function for a certain input value. In the exercise, we are given the function \( f(x) = x^{-0.71} \), which means that **x** will be raised to the power of -0.71. To evaluate this function at a specific value of **x**, such as 3.8, we simply substitute 3.8 in place of **x**.
* Here's how it works step by step: * Identify the function: **f(x) = x^{-0.71}** * Substitute the x value: **f(3.8) = (3.8)^{-0.71}**
This substitution allows us to turn the algebraic function into a numerical expression that we can solve. For complex functions or unusual exponents like -0.71, using a calculator is often the best way to evaluate the function accurately without human error.
Approximation
Approximation refers to the process of finding a number that is close enough to the exact answer, usually by following a certain rule or method. In mathematics, sometimes it's more practical to work with a rough estimate of a number than to use its exact value.
* **Why do we approximate?** * Simplifying complex numbers * Making calculations more manageable * Conveying information more easily
In the example with \((3.8)^{-0.71}\), we approximate to a certain number of decimal places. Upon calculating, we find \((3.8)^{-0.71} \approx 0.408\). Instead of keeping all the decimal places, it's often preferable to use a shorter number for simplicity, especially in real-world contexts where an ultra-precise number is not necessary.
Rounding Numbers
Rounding is a mathematical technique that reduces the number of digits without losing the essence of the number. It helps make numbers simpler to work with and more comprehensible.
* **How does rounding work?** * Decide which place you want to round to (e.g., nearest hundredth) * Look at the digit immediately after that place * If the digit is 5 or more, round the number up * If it's 4 or less, keep it the same
In the context of our problem, after evaluating the function and obtaining an approximation of **0.408**, we examine the third decimal place (which is 8) to decide on rounding. Since 8 is greater than 5, we round up the second decimal place from 0, resulting in **0.41**. Rounding, therefore, makes this number easier to use and communicate.

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Most popular questions from this chapter

Solve each problem. See Example 9. The strength \(S\) of a rectangular beam varies directly with its width \(W\) and the square of its thickness \(T,\) and inversely with its length \(L\). A beam that is 2 inches wide, 6 inches thick, and 96 inches long can support a load of 375 pounds. Determine how much a similar beam that is 3.5 inches wide, 8 inches thick, and 128 inches long can support.

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