Chapter 4: Problem 23
Find all complex solutions for each equation by hand. Do not use a calculator. $$x^{-4}-3 x^{-2}-4=0$$
Short Answer
Expert verified
The complex solutions are \( x = \frac{1}{2}, -\frac{1}{2}, i, -i \).
Step by step solution
01
Substitution
Let us begin by substituting a new variable to make the equation simpler. Let \( y = x^{-2} \). That means \( y^2 = (x^{-2})^2 = x^{-4} \). This allows us to rewrite the original equation \( x^{-4} - 3x^{-2} - 4 = 0 \) as \( y^2 - 3y - 4 = 0 \).
02
Solve the Quadratic Equation
Now solve the quadratic equation \( y^2 - 3y - 4 = 0 \) using the quadratic formula: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \( a = 1, b = -3, c = -4 \). Substitute these values into the formula: \[ y = \frac{3 \pm \sqrt{(-3)^2 - 4 \times 1 \times (-4)}}{2 \times 1} = \frac{3 \pm \sqrt{9 + 16}}{2} = \frac{3 \pm \sqrt{25}}{2} = \frac{3 \pm 5}{2} \]. This gives two solutions: \( y = 4 \) and \( y = -1 \).
03
Resubstitution to Original Variable
Replace \( y \) with \( x^{-2} \). The two cases are \( x^{-2} = 4 \) and \( x^{-2} = -1 \).
04
Solve for x (Case 1, x^{-2} = 4)
If \( x^{-2} = 4 \), then take the reciprocal to get \( x^2 = \frac{1}{4} \). Solving this gives \( x = \pm \frac{1}{2} \). Therefore, the solutions for this case are \( x = \frac{1}{2} \) and \( x = -\frac{1}{2} \).
05
Solve for x (Case 2, x^{-2} = -1)
If \( x^{-2} = -1 \), taking the reciprocal gives \( x^2 = -1 \). The solutions to this equation are complex numbers, \( x = i \) and \( x = -i \), where \( i \) is the imaginary unit.
06
Conclusion
Combine all solutions found from both cases together. The complete set of complex solutions for the equation \( x^{-4} - 3x^{-2} - 4 = 0 \) is \( x = \frac{1}{2}, -\frac{1}{2}, i, -i \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Quadratic Equations
A quadratic equation is a fundamental concept in mathematics. It is a polynomial equation of degree 2, generally taking the form: \[ ax^2 + bx + c = 0 \] where \( a \), \( b \), and \( c \) are constants with \( a eq 0 \). Quadratic equations form a parabola when graphed. The solutions to a quadratic equation are the points where this parabola intersects the x-axis. These solutions can be real or complex.
- Real solutions: These occur when the discriminant \( b^2 - 4ac \) is positive or zero.
- Complex or imaginary solutions: These occur when the discriminant is negative. They include the imaginary unit \( i \), which has the property \( i^2 = -1 \).
The Role of the Imaginary Unit
In mathematics, the imaginary unit is crucial for expanding the number system to include complex numbers. It is represented by \( i \) and defined by the property that \( i^2 = -1 \). This lets us solve equations involving negative values under the square root, such as \( x^2 = -1 \). When we solve such an equation, the solutions are \( x = i \) and \( x = -i \). These solutions form part of what we call complex solutions. Complex numbers consist of two parts: a real part and an imaginary part.
- Real part: For example, in \( 3 + 4i \), the real part is 3.
- Imaginary part: The imaginary part in \( 3 + 4i \) is 4i.
Exploring Variable Substitution
Variable substitution is a powerful technique often used to simplify complicated equations, especially those that are polynomial in nature. The essence of substitution involves replacing a variable or expression within an equation with another simpler variable or expression.In our original exercise, we dealt with the equation: \[ x^{-4} - 3x^{-2} - 4 = 0 \] To simplify this equation, we used the substitution \( y = x^{-2} \). This transformed the problem into a standard quadratic form: \[ y^2 - 3y - 4 = 0 \] This step made the equation easier to manage, allowing the application of the quadratic formula. After solving the quadratic form, re-substitution was necessary to revert to the original variable format.
- Initial substitution: Simplifies the equation by reducing complexity.
- Solving the equation: Using methods such as factoring, completing the square, or applying the quadratic formula.
- Re-substitution: Converts the solution back to the original problem's variable context.