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For each quadratic function defined , (a) write the function in the form \(P(x)=a(x-h)^{2}+k,\) (b) give the vertex of the parabola, and (c) graph the function. Do not use a calculator. $$P(x)=-x^{2}-3 x+10$$

Short Answer

Expert verified
Write as \( P(x) = - (x+\frac{3}{2})^2 + \frac{49}{4} \), vertex at \( (-\frac{3}{2}, \frac{49}{4}) \).

Step by step solution

01

Completing the Square

The quadratic function given is \( P(x) = -x^{2} - 3x + 10 \). To rewrite this in the form \( P(x) = a(x-h)^{2} + k \), we need to complete the square for the quadratic terms. First, factor out \(-1\) from the quadratic and linear terms:\[ P(x) = - (x^2 + 3x) + 10 \]Now, to complete the square inside the parenthesis, take the coefficient of \(x\), which is 3, divide it by 2 to get \(\frac{3}{2}\), and square it to get \(\left(\frac{3}{2}\right)^2 = \frac{9}{4}\). Add and subtract this square inside the parenthesis:\[ P(x) = - \left( x^2 + 3x + \frac{9}{4} - \frac{9}{4} \right) + 10 \]Now, rearrange:\[ P(x) = - \left( (x + \frac{3}{2})^2 - \frac{9}{4} \right) + 10 \]
02

Expanding the Square and Simplifying

Expand the expression:\[ P(x) = - (x + \frac{3}{2})^2 + \frac{9}{4} + 10 \]Combine the constants to simplify:\[ P(x) = - (x + \frac{3}{2})^2 + \frac{49}{4} \]
03

Identifying the Vertex

The function is now in the form \( P(x) = a(x-h)^2 + k \), where \( a = -1 \), \( h = -\frac{3}{2} \), and \( k = \frac{49}{4} \).So, the vertex of the parabola is \( \left( -\frac{3}{2}, \frac{49}{4} \right) \).
04

Graphing the Function

To graph the function, note the vertex is \( \left( -\frac{3}{2}, \frac{49}{4} \right) \). Since \( a = -1 \), the parabola opens downward. Plot the vertex on the graph. Use additional points around the vertex, such as \(x = -1\) and \(x = -2\), to get the shape. Calculate:For \(x = -1\), \( P(x) = -(-1+\frac{3}{2})^2 + \frac{49}{4} = -\left(\frac{1}{2}\right)^2 + \frac{49}{4} = \frac{47}{4} \).For \(x = -2\), \( P(x) = -(-2+\frac{3}{2})^2 + \frac{49}{4} = -\left(-\frac{1}{2}\right)^2 + \frac{49}{4} = \frac{47}{4} \).The point \((x = -1, P(x) = \frac{47}{4})\) and \((x = -2, P(x) = \frac{47}{4})\) also lie on the curve, creating the parabola's downward shape.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Completing the Square
Completing the square is a technique used to rewrite quadratic expressions in a specific form, which helps simplify solving and graphing these equations. Given the quadratic function \[ P(x) = -x^2 - 3x + 10, \]we begin by focusing on the quadratic and linear terms. The idea is to form a perfect square trinomial.

Start by factoring out -1 from the quadratic and linear terms, so we have:\[ P(x) = - (x^2 + 3x) + 10. \]The next step is to "complete the square" inside the parenthesis. This involves:
  • Taking the coefficient of the linear term, which is 3,
  • Dividing it by 2 to get \( \frac{3}{2}, \)
  • Squaring it to get \( \left( \frac{3}{2} \right)^2 = \frac{9}{4}. \)
We then add and subtract this square inside the parenthesis:\[ P(x) = - \left( x^2 + 3x + \frac{9}{4} - \frac{9}{4} \right) + 10. \]This creates a perfect square trinomial:\[ P(x) = - \left( (x + \frac{3}{2})^2 - \frac{9}{4} \right) + 10. \]Once in this form, we simplify to prepare for graphing and identifying other key features.
Vertex Form
Vertex form of a quadratic function allows us to easily identify key elements of the parabola, such as its vertex. Once we complete the square, our function is in the form:\[ P(x) = a(x-h)^2 + k, \]where \( a \), \( h \), and \( k \) are constants. For the function above, this results in:\[ P(x) = - (x + \frac{3}{2})^2 + \frac{9}{4} + 10. \]After simplifying the constants, we have:\[ P(x) = - (x + \frac{3}{2})^2 + \frac{49}{4}. \]

In this form:
  • \( a = -1 \) indicates that the parabola opens downward,
  • \( h = -\frac{3}{2} \) and \( k = \frac{49}{4} \) reveal the vertex of the parabola located at \( \left( -\frac{3}{2}, \frac{49}{4} \right) \).
By having the function in vertex form, it becomes straightforward to graph it by plotting the vertex and recognizing its symmetrical properties.
Graphing Parabolas
Graphing a parabola involves plotting points to reveal the curve's shape and direction. With the quadratic in vertex form:\[ P(x) = - (x + \frac{3}{2})^2 + \frac{49}{4}, \]we know that the parabola opens downward because \( a = -1. \) The vertex, \( \left( -\frac{3}{2}, \frac{49}{4} \right), \) is the highest point.

To accurately depict the parabola:
  • Plot the vertex on the graph.
  • Determine additional points using values around the vertex, such as \( x = -1 \) and \( x = -2. \)
For these values:
  • When \( x = -1, \) \( P(x) = \frac{47}{4}. \)
  • When \( x = -2, \) the calculation similarly yields \( P(x) = \frac{47}{4}. \)
These points help outline the parabola's symmetrical and downward-opening structure. By connecting these points smoothly, you'll have a clear graph of the quadratic function, showing the parabola's full curve.

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