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Multiply as indicated. Write each product in standard form. $$(-3+2 i)^{2}$$

Short Answer

Expert verified
The product is \(5 - 12i\).

Step by step solution

01

Expand the Square

Apply the formula \((a + b)^2 = a^2 + 2ab + b^2\) to \((-3 + 2i)^2\) where \(a = -3\) and \(b = 2i\). This gives us:\[(-3 + 2i)^2 = (-3)^2 + 2(-3)(2i) + (2i)^2\]
02

Calculate Each Term

Calculate each term separately:- \((-3)^2 = 9\)- \(2(-3)(2i) = -12i\)- \((2i)^2 = 4i^2 = 4(-1) = -4\) (since \(i^2 = -1\))
03

Combine the Terms

Combine the real and imaginary parts:\[9 - 4 - 12i = 5 - 12i\]
04

Write in Standard Form

The expression is now in a standard form \(a + bi\), so the final answer is:\[5 - 12i\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Numbers
Imaginary numbers are fascinating and often misunderstood components of the number system. They stem from the necessity to find the square roots of negative numbers, which is not possible with just real numbers. The basic imaginary unit is denoted as \( i \), where \( i \) is defined by its property \( i^2 = -1 \). This allows mathematicians to express numbers that include an imaginary part.

Imaginary numbers are particularly useful in complex numbers. A complex number is typically expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( bi \) represents the imaginary part. This format elegantly combines real numbers with imaginary numbers, allowing more complex equations to be solved.
  • Example: The number \( 3 + 4i \) has a real part of 3 and an imaginary part of 4.
  • Application: Imaginary numbers are not just theoretical constructs. They are widely used in engineering fields, including electrical engineering, where they help in analyzing circuits.
Polynomial Expansion
Polynomial expansion involves rewriting expressions in a form that makes them easier to work with. A common task is expanding binomials using a formula, such as \((a + b)^2 = a^2 + 2ab + b^2\).

In the given problem, we expand \((-3 + 2i)^2\) using this formula. Here's why it's helpful:
  • The provided formula allows us to systematically find each part of the expression by multiplying out each term.
  • First, we calculate \((-3)^2\), which results in 9, the real component.
  • Then, we find the cross-product \(2(-3)(2i) = -12i\), representing an interaction between real and imaginary parts.
  • Lastly, calculating \((2i)^2\), which is \(4i^2 = -4\), gives another real part when considering \(i^2 = -1\).
This method is crucial because it converts a complicated expression into simpler pieces that can be added together to form a straightforward result.
Standard Form
In mathematics, expressing complex numbers in their standard form is important for clarity and consistency. The standard form of a complex number is expressed as \( a + bi \), where \( a \) is the real part and \( bi \) is the imaginary part.

This form makes it easier to identify the real and imaginary components of a number, which is useful in various computations and applications.
  • Mathematically, as seen in our exercise, \( (-3 + 2i)^2 = 5 - 12i \) is simplified into a standard form.
  • This standardization aids in simplifying arithmetic operations involving complex numbers, ensuring easier calculations and interpretations.
  • Real-life applications of complex numbers in standard form include alternating current (AC) circuit analysis and signal processing.
By learning to express complex numbers in standard form, students gain a powerful tool for tackling advanced mathematical problems with more confidence and ease.

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Most popular questions from this chapter

Use Descartes' rule of signs to determine the possible numbers of positive and negative real zeros for \(P(x) .\) Then, use a graph to determine the actual numbers of positive and negative real zeros. $$P(x)=5 x^{4}+3 x^{2}+2 x-9$$

Draw by hand a rough sketch of the graph of each function. (You may wish to support your answer with a calculator graph.) $$\begin{aligned}P(x) &=2 x^{5}-10 x^{4}+x^{3}-5 x^{2}-x+5 \\\&=(x-5)\left(x^{2}+1\right)\left(2 x^{2}-1\right)\end{aligned}$$

Sketch a graph of a quadratic function that satisfies each set of given conditions. Use symmetry to label another point on your graph. Vertex \((5,6) ;\) through \((1,-6)\)

For each polynomial function, do the following in order. (a) Use Descartes' rule of signs to find the possible number of positive and negative real zeros. (b) Use the rational zeros theorem to determine the possible rational zeros of the function. (c) Find the rational zeros, if any. (d) Find all other real zeros, if any. (e) Find any other nonreal complex zeros, if any. (f) Find the \(x\) -intercepts of the graph, if any. (g) Find the \(y\) -intercept of the graph. (h) Use synthetic division to find \(P(4),\) and give the coordinates of the corresponding point on the graph. (i) Determine the end behavior of the graph. (i) Sketch the graph. (You may wish to support your answer with a calculator graph.) $$P(x)=-x^{5}-x^{4}+10 x^{3}+10 x^{2}-9 x-9$$

For each polynomial, at least one zero is given. Find all others analytically. $$P(x)=x^{4}-52 x^{2}+147 ; \quad-7 \text { and } 7$$

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