Chapter 3: Problem 58
Solve each equation. For equations with real solutions, support your answers graphically. $$-5 x^{2}+28 x+12=0$$
Short Answer
Expert verified
The solutions are \( x = -0.4 \) and \( x = 6 \).
Step by step solution
01
Identify the Quadratic Equation Structure
The given equation is \[-5x^2 + 28x + 12 = 0.\] This is a quadratic equation in standard form, where \( a = -5 \), \( b = 28 \), and \( c = 12 \). Our goal is to find the real values of \( x \) that satisfy this equation.
02
Use the Quadratic Formula
The quadratic formula is given by\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\]Substitute \( a = -5 \), \( b = 28 \), and \( c = 12 \) into the formula:\[ x = \frac{-28 \pm \sqrt{28^2 - 4(-5)(12)}}{2(-5)}.\]
03
Solve the Discriminant
First, calculate the discriminant, \( b^2 - 4ac \):\[ 28^2 - 4(-5)(12) = 784 + 240 = 1024.\]Since the discriminant is positive, there are two distinct real solutions.
04
Calculate the Solutions
Substitute the discriminant back into the quadratic formula:\[ x = \frac{-28 \pm \sqrt{1024}}{-10}.\]The square root of 1024 is 32, so the equation becomes:\[ x = \frac{-28 \pm 32}{-10}.\]Calculate the two possible values for \( x \):1. \( x = \frac{-28 + 32}{-10} = \frac{4}{-10} = -0.4.\)2. \( x = \frac{-28 - 32}{-10} = \frac{-60}{-10} = 6.\)
05
Verify Solutions Graphically
A quadratic function can be graphed to verify the roots. Graph the function \( y = -5x^2 + 28x + 12 \). Observe where the parabola intersects the x-axis. The points of intersection represent the solutions. On the graph, it will intersect at \( x = -0.4 \) and \( x = 6 \), confirming the solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The Quadratic Formula is a fundamental tool for solving quadratic equations. These equations typically have the form \( ax^2 + bx + c = 0 \). In our example, we've been given an equation \(-5x^2 + 28x + 12 = 0\). This aligns with the standard quadratic equation format where \(a = -5\), \(b = 28\), and \(c = 12\).
Here’s a refresher on why the quadratic formula is so handy:
Here’s a refresher on why the quadratic formula is so handy:
- It provides a direct method for finding roots, or solutions, of a quadratic equation.
- The formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Discriminant
The discriminant is an integral component of the quadratic formula and provides crucial insight into the nature of the solutions of a quadratic equation. It is found in the part of the quadratic formula under the square root:
A positive discriminant value, as in this case:
- The discriminant, represented by \( b^2 - 4ac \), helps determine the number and type of solutions.
A positive discriminant value, as in this case:
- Indicates that there are two distinct real solutions.
Graphing Quadratics
Graphing quadratic equations helps visually confirm the solutions found through algebraic methods. A quadratic equation like \(-5x^2 + 28x + 12 = 0\) forms a parabola when graphed. The key steps to visualizing such graphs involve:
- Identifying the vertex and axis of symmetry.
- Determining how the graph opens, based on the sign of \(a\). A negative \(a\) indicates the parabola opens downwards.
- They illustrate how the vertex and direction of opening affect the overall graph.
- Graphs provide insight into maximum and minimum values and the range of possible \(y\)-values.