Chapter 3: Problem 56
Solve each equation. For equations with real solutions, support your answers graphically. $$9 x^{2}+12 x+4=0$$
Short Answer
Expert verified
The solution is \( x = -\frac{2}{3} \), confirmed graphically by the parabola touching the x-axis at the vertex.
Step by step solution
01
Identify the Quadratic Equation
The given equation is in the standard form of a quadratic equation: \( ax^2 + bx + c = 0 \). For this equation, \( a = 9 \), \( b = 12 \), and \( c = 4 \).
02
Determine the Discriminant
The discriminant \( D \) of a quadratic equation is given by \( D = b^2 - 4ac \). We plug in the values: \( D = 12^2 - 4 \times 9 \times 4 \). Calculate \( D = 144 - 144 = 0 \).
03
Interpret the Discriminant
Since the discriminant \( D = 0 \), the quadratic equation has exactly one real solution, meaning it is a perfect square trinomial.
04
Factor the Quadratic
A discriminant of zero suggests that the quadratic can be factored as a perfect square. The equation can be written as \((3x + 2)^2 = 0\).
05
Solve the Equation
Set the factored form equal to zero and solve for \( x \): \((3x + 2)^2 = 0\) implies \(3x + 2 = 0\). Solving for \( x \), we get \(3x = -2\) which simplifies to \(x = -\frac{2}{3}\).
06
Support with Graphical Representation
Graph the quadratic function \( y = 9x^2 + 12x + 4 \). The vertex of this parabola is at \((-\frac{2}{3}, 0)\), which confirms the root. The parabola touches the x-axis at its vertex, supporting the presence of exactly one real root.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
In quadratic equations, the concept of the discriminant is like a key that unlocks information about the nature of roots. For the standard quadratic equation \( ax^2 + bx + c = 0 \), the discriminant \( D \) is calculated using the formula \( D = b^2 - 4ac \). Based on its value, you can predict the type of roots without actually solving the equation.
- If \( D > 0 \), the equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root. This indicates that the quadratic is a perfect square trinomial.
- If \( D < 0 \), there are no real roots, but two complex roots instead.
In our original equation, the discriminant was calculated as 0, indicating that it's a perfect square trinomial with one real root.
- If \( D > 0 \), the equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root. This indicates that the quadratic is a perfect square trinomial.
- If \( D < 0 \), there are no real roots, but two complex roots instead.
In our original equation, the discriminant was calculated as 0, indicating that it's a perfect square trinomial with one real root.
Factoring
The process of factoring is simplifying the quadratic expression into products of simpler expressions. This step is particularly useful when you have a discriminant of zero, indicating a perfect square trinomial. If a quadratic equation can be factored, it can be written as \((px + q)^2 = 0\), greatly simplifying the problem of finding solutions.
For the problem \( 9x^2 + 12x + 4 = 0 \), once we identified the discriminant as zero, it offered a clue that the quadratic could be expressed as a square of a binomial. Indeed, the factoring process revealed this as \((3x + 2)^2 = 0\). Solving \((3x + 2)^2 = 0\) efficiently gives us the root \(x = -\frac{2}{3}\).
This insight phases out complex solving steps, providing a straightforward path to the solution.
For the problem \( 9x^2 + 12x + 4 = 0 \), once we identified the discriminant as zero, it offered a clue that the quadratic could be expressed as a square of a binomial. Indeed, the factoring process revealed this as \((3x + 2)^2 = 0\). Solving \((3x + 2)^2 = 0\) efficiently gives us the root \(x = -\frac{2}{3}\).
This insight phases out complex solving steps, providing a straightforward path to the solution.
Graphical Representation
Visualizing quadratic equations through graphs can offer intuitive insights into the roots and behavior of the equation. The equation \( y = ax^2 + bx + c \) models a parabola in the coordinate plane. The properties of the discriminant influence the graph's appearance.
- A positive discriminant \( D > 0 \) results in a graph that intersects the x-axis at two distinct points (two real roots).
- A zero discriminant \( D = 0 \) shows a graph that is tangent to the x-axis, touching it at exactly one point (one real root).
- A negative discriminant \( D < 0 \) means the graph does not intersect the x-axis (complex roots).
In our exercise, the equation \( y = 9x^2 + 12x + 4 \) graphs as a parabola that just touches the x-axis at the vertex \((-\frac{2}{3}, 0)\), visually confirming the presence of one real root.
- A positive discriminant \( D > 0 \) results in a graph that intersects the x-axis at two distinct points (two real roots).
- A zero discriminant \( D = 0 \) shows a graph that is tangent to the x-axis, touching it at exactly one point (one real root).
- A negative discriminant \( D < 0 \) means the graph does not intersect the x-axis (complex roots).
In our exercise, the equation \( y = 9x^2 + 12x + 4 \) graphs as a parabola that just touches the x-axis at the vertex \((-\frac{2}{3}, 0)\), visually confirming the presence of one real root.
Real Roots
The concept of real roots is central to solving quadratic equations, focused on finding values for \( x \) that satisfy the equation \( ax^2 + bx + c = 0 \). Real roots mean that the equation's solutions are numbers that intersect the x-axis in a graph.
Real roots vary in nature:
Real roots vary in nature:
- Two distinct real roots arise when \( D > 0 \), producing a parabola that crosses the x-axis at two points.
- A single real root occurs when \( D = 0 \), indicating the parabola touches the x-axis just once, as a perfect square trinomial.
- No real roots are found when \( D < 0 \), leading to intersections that do not reach the x-axis.