Chapter 3: Problem 38
Solve each equation. For equations with real solutions, support your answers graphically. $$x^{2}+8 x+13=0$$
Short Answer
Expert verified
The solutions are \( x = -4 + \sqrt{3} \) and \( x = -4 - \sqrt{3} \).
Step by step solution
01
Identify the Quadratic Equation
We are given a quadratic equation in the form \( ax^2 + bx + c = 0 \), where \( a = 1 \), \( b = 8 \), and \( c = 13 \). Our goal is to solve for \( x \).
02
Calculate the Discriminant
The discriminant \( D \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( D = b^2 - 4ac \). Substitute the values: \( D = 8^2 - 4(1)(13) = 64 - 52 = 12 \). Since \( D > 0 \), the equation has two distinct real solutions.
03
Use Quadratic Formula to Find Solutions
The quadratic formula \( x = \frac{-b \pm \sqrt{D}}{2a} \) is used to find the roots. Substituting \( b = 8 \), \( D = 12 \), and \( a = 1 \), we get: \( x = \frac{-8 \pm \sqrt{12}}{2} \). Simplifying \( \sqrt{12} \), we get \( 2\sqrt{3} \). Thus, \( x = \frac{-8 \pm 2\sqrt{3}}{2} = -4 \pm \sqrt{3} \).
04
Graphical Interpretation
Graph the quadratic equation \( y = x^2 + 8x + 13 \) using a graphing tool. The graph is a parabola that opens upwards. The roots \( x = -4 + \sqrt{3} \) and \( x = -4 - \sqrt{3} \) are where the curve intersects the x-axis. These graphical points verify our solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Discriminant
The discriminant is a critical component of quadratic equations that tells us about the nature of the roots without solving the equation completely. For any quadratic equation of the form \( ax^2 + bx + c = 0 \), the discriminant \( D \) is calculated using the formula \( D = b^2 - 4ac \). Here are some essential details to know about the discriminant:
- If \( D > 0 \), the quadratic equation has two distinct real roots, meaning it will cross the x-axis at two points.
- If \( D = 0 \), there is exactly one real root, also known as a repeated or double root. The parabola will touch the x-axis but not cross it.
- If \( D < 0 \), the equation has no real roots, indicating that the parabola does not intersect the x-axis at any point.
Solving with the Quadratic Formula
The quadratic formula is a powerful tool for finding the roots of any quadratic equation, especially when factoring is complex or the roots are not immediately apparent. The formula is given by:
\[ x = \frac{-b \pm \sqrt{D}}{2a} \]
where \( a \), \( b \), and \( D \) are coefficients and the discriminant derived from \( ax^2 + bx + c = 0 \). This method is nearly universal for solving quadratic equations.
In our exercise, using the values \( a = 1 \), \( b = 8 \), and \( D = 12 \), we substitute these into the formula:
\[ x = \frac{-b \pm \sqrt{D}}{2a} \]
where \( a \), \( b \), and \( D \) are coefficients and the discriminant derived from \( ax^2 + bx + c = 0 \). This method is nearly universal for solving quadratic equations.
In our exercise, using the values \( a = 1 \), \( b = 8 \), and \( D = 12 \), we substitute these into the formula:
- Calculate \( -b = -8 \)
- Compute \( \sqrt{12} = 2\sqrt{3} \)
- Substitute into the formula, simplifying to \( x = -4 \pm \sqrt{3} \)
Graphical Solutions of Quadratic Equations
Graphical solutions provide a visual way to determine the roots of a quadratic equation. The graph of a quadratic equation is a parabola. Its shape, determined by the coefficient \( a \), can open upwards if \( a > 0 \) or downwards if \( a < 0 \). To find the roots graphically, we look for where the parabola intersects the x-axis.
- If the discriminant \( D > 0 \), the parabola will cross the x-axis at two distinct points, corresponding to the two real roots.
- If \( D = 0 \), the parabola touches the x-axis at exactly one point, indicating a repeated root.
- If \( D < 0 \), the parabola does not intersect with the x-axis, confirming there are no real roots.