Chapter 3: Problem 35
Solve each equation. For equations with real solutions, support your answers graphically. $$(x+2)(x-1)=7 x+5$$
Short Answer
Expert verified
The solutions are \(x = 7\) and \(x = -1\).
Step by step solution
01
Expand the Left Side
First, we need to expand the left side of the equation \((x+2)(x-1)\). Apply the distributive property:\[(x+2)(x-1) = x(x) + x(-1) + 2(x) + 2(-1) = x^2 - x + 2x - 2\].Combine like terms:\[x^2 + x - 2\]. This simplifies the equation to \(x^2 + x - 2 = 7x + 5\).
02
Move All Terms to One Side
To make the equation easier to solve, we'll subtract \(7x\) and \(5\) from both sides to set the equation to zero:\[x^2 + x - 2 - 7x - 5 = 0\].Simplify the terms to get:\[x^2 - 6x - 7 = 0\].
03
Factor the Quadratic Equation
We now need to factor the quadratic equation \(x^2 - 6x - 7 = 0\). The factors of \(-7\) that add to \(-6\) are \(-7\) and \(1\).Thus, the equation factors as:\((x - 7)(x + 1) = 0\).
04
Solve for x
Set each factor equal to zero to find the solutions for \(x\):1. \(x - 7 = 0\) leads to \(x = 7\).2. \(x + 1 = 0\) leads to \(x = -1\).
05
Verify Graphically
Sketch the graph of two functions: \(y = (x+2)(x-1)\) and \(y = 7x+5\).- The quadratic \(y = (x+2)(x-1)\) will be a parabola opening upwards.- The linear function \(y = 7x+5\) will be a straight line.Check where these two graphs intersect, which should be at the solutions \(x = 7\) and \(x = -1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Quadratics
Factoring quadratic equations is a powerful method for finding solutions or "roots" of these equations. A quadratic equation is any equation of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. The goal of factoring is to rewrite the quadratic as a product of two binomials:
- Identify a pair of numbers that multiply to \(c\) (the constant term) and add to \(b\) (the linear coefficient).
- Write the quadratic expression as a product of two binomials using these numbers.
Graphical Solutions
Graphical solutions offer a visual representation of where two functions intersect, which represent the solutions to the equation. In our specific example,
- The quadratic equation \((x+2)(x-1)\) when expanded forms the parabola \(y = x^2 + x - 2\).
- The linear equation \(y = 7x + 5\) creates a straight line when graphed.
Distributive Property
The distributive property is a fundamental algebraic concept used to multiply a single term across terms within parentheses. It states that for any numbers or expressions \(a\), \(b\), and \(c\), the equation \(a(b+c) = ab + ac\) holds true. In quadratic equations, the distributive property helps expand expressions.
- Starting with \((x+2)(x-1)\), the property allows you to systematically multiply each term, resulting in \(x(x) + x(-1) + 2(x) + 2(-1)\).
- This expansion process step-by-step leads to \(x^2 - x + 2x - 2\), simplifying to \(x^2 + x - 2\).