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Use \(f(x)\) and \(g(x)\) to find each composition. Identify its domain. (Use a calculator if necessary to find the domain.) (a) \((f \circ g)(x) \quad\) (b) \((g \circ f)(x) \quad\) (c) \((f \circ f)(x)\). $$f(x)=2-x, \quad g(x)=\frac{1}{x^{2}}$$

Short Answer

Expert verified
(a) \((f \circ g)(x) = 2 - \frac{1}{x^2}\), domain: \(x \neq 0\). (b) \((g \circ f)(x) = \frac{1}{(2-x)^2}\), domain: \(x \neq 2\). (c) \((f \circ f)(x) = x\), domain: \(x \in \mathbb{R}\).

Step by step solution

01

Find \((f \, \circ \, g)(x)\)

To find \((f \circ g)(x)\), we need to substitute \(g(x)\) into \(f(x)\). This means we replace \(x\) in \(f(x) = 2 - x\) with \(g(x) = \frac{1}{x^2}\). Thus, \((f \circ g)(x) = f(g(x)) = 2 - \frac{1}{x^2} = 2 - \frac{1}{x^2}.\)Next, determine the domain, which is all real values where \(g(x)\) is defined and \(2 - \frac{1}{x^2}\) is also defined. Since \(g(x)\) is undefined for \(x = 0\), the domain is all real numbers except \(x = 0\).
02

Identify the Domain of \((f \, \circ \, g)(x)\)

The domain of \((f \circ g)(x) = 2 - \frac{1}{x^2}\) is determined by the restrictions from \(g(x) = \frac{1}{x^2}\). As \(x = 0\) makes \(g(x)\) undefined, the domain is \, \(-\infty, 0\) or \((0, \infty)\). Therefore, the domain of \((f \circ g)(x)\) is \, \(x eq 0\).
03

Find \((g \, \circ \, f)(x)\)

To find \((g \circ f)(x)\), substitute \(f(x)\) into \(g(x)\), changing \(x\) in \(g(x) = \frac{1}{x^2}\) with \(f(x) = 2 - x\). This yields \((g \circ f)(x) = g(f(x)) = \frac{1}{(2-x)^2}.\)Next, determine the domain by ensuring \((2-x) eq 0\) which gives \(x eq 2\). Therefore, the domain is all real numbers except \(x = 2\).
04

Identify the Domain of \((g \, \circ \, f)(x)\)

The domain of \((g \circ f)(x) = \frac{1}{(2-x)^2}\) is defined everywhere except where the denominator equals zero. Thus, the domain is \, \(x eq 2\).
05

Find \((f \, \circ \, f)(x)\)

To find \((f \circ f)(x)\), substitute \(f(x)\) into itself, replacing \(x\) in \(f(x) = 2 - x\) with \(f(x) = 2 - x\). This results in:\((f \circ f)(x) = f(f(x)) = 2 - (2 - x) = x.\)Thus, \((f \circ f)(x) = x\), which is defined for all real numbers. Therefore, the domain is all real numbers \(x \in \mathbb{R}\).
06

Identify the Domain of \((f \, \circ \, f)(x)\)

Since \((f \circ f)(x) = x\), it is valid for all real numbers. Therefore, the domain is \(x \in \mathbb{R}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of Functions
Understanding the domain of a function is fundamental in mathematics. The domain of a function refers to all possible input values (usually denoted by \(x\)) that will not lead to a mathematical error when input into the function. Examples of such errors include division by zero or taking square roots of negative numbers.

For instance, with the function \(g(x) = \frac{1}{x^2}\), the domain is all real numbers except \(x = 0\) because division by zero is undefined in mathematics. We represent the domain of \(g(x)\) with the interval notation \((-\infty, 0) \cup (0, \infty)\).

Similarly, when finding the domain of compositions like \((f \circ g)(x)\), it's crucial to consider the individual domains of both \(f(x)\) and \(g(x)\). In this case, due to the domain restriction of \(g(x)\), the domain of \((f \circ g)(x)\) also excludes \(x = 0\). So, when tackling function compositions, always remember to take their domains into account.
Composition of Functions
Function composition is a vital concept in algebra that involves applying one function to the results of another. Represented as \((f \circ g)(x) = f(g(x))\), it essentially means the output of function \(g(x)\) becomes the input of function \(f(x)\).

For the problem given, where \(f(x) = 2 - x\) and \(g(x) = \frac{1}{x^2}\), when you compose \(f\) and \(g\), you substitute the expression for \(g(x)\) into \(f(x)\). This results in \((f \circ g)(x) = 2 - \frac{1}{x^2}\).

But it's not just about substitution; understanding each function's role in the composition is also key. \(g(x)\) modifies the input by inverting and squaring it, and then \(f(x)\) further modifies the result by subtracting from 2. Such layers of operations demonstrate how complex functions can be built from simpler ones, which is the essence of composition.
Algebraic Functions
Algebraic functions include expressions like polynomials, rational functions, and radicals, which can be constructed using algebraic operations such as addition, subtraction, multiplication, division, and extraction of roots. These functions form the backbone of many problems in mathematics.

In our exercise, both \(f(x) = 2 - x\) and \(g(x) = \frac{1}{x^2}\) are algebraic functions. \(f(x)\) is a polynomial of degree one, making it a simple linear function, while \(g(x)\) is a rational function, specifically a fraction with a polynomial in the denominator.

Understanding their properties individually aids in comprehending how they behave when combined in compositions. When a function like \(g(x) = \frac{1}{x^2}\) which involves division, is combined with \(f(x)\), the resulting function \((f \circ g)(x) = 2 - \frac{1}{x^2}\) still shares properties of both algebraic parents, possessing linearity from \(f\) and rational characteristics from \(g\). This inheritance of properties is a key feature of algebraic functions.

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Most popular questions from this chapter

Solve each problem. Systolic blood pressure is the maximum pressure produced by each heartbeat. Both low blood pressure and high blood pressure are cause for medical concern. Therefore, health care professionals are interested in a patient's "pressure difference from normal," or \(P_{d}\). If 120 is considered a normal systolic pressure, \(P_{d}=|P-120|,\) where \(P\) is the patient's recorded systolic pressure. For example, a patient with a systolic pressure \(P\) of 113 would have a pressure difference from normal of \(P_{d}=|P-120|=|113-120|=|-7|=7\) (a) Calculate the \(P_{d}\) value for a woman whose actual systolic pressure is 116 and whose normal value should be 125 (b) If a patient's \(P_{d}\) value is 17 and the normal pressure for his sex and age should be \(120,\) what are the two possible values for his systolic blood pressure?

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