Chapter 2: Problem 5
Skills For each piecewise-defined function, find (a) \(f(-5),\) (b) \(f(-1),\) (c) \(f(0),\) and (d) \(f(3)\) ) Do not use a calculator. $$f(x)=\left\\{\begin{array}{ll} 2 x & \text { if } x \leq-1 \\ x-1 & \text { if } x>-1 \end{array}\right.$$
Short Answer
Expert verified
(a) -10, (b) -2, (c) -1, (d) 2.
Step by step solution
01
Identify which function to use for f(-5)
The given function is defined as a piecewise function with two parts: \[ \begin{array}{ll} f(x) = 2x & \text{for } x \leq -1 \ f(x) = x - 1 & \text{for } x > -1 \end{array} \]Since \(-5 \leq -1\), we use the first function, \( f(x) = 2x \), to find \( f(-5) \).
02
Calculate f(-5)
Using the function \( f(x) = 2x \), substitute \( x = -5 \) into the equation:\[ f(-5) = 2(-5) = -10 \]
03
Identify which function to use for f(-1)
For \( f(-1) \), notice that \(-1 \leq -1\). This means we should use the function \( f(x) = 2x \) since \( x \leq -1 \).
04
Calculate f(-1)
Substitute \( x = -1 \) into the first function \( f(x) = 2x \):\[ f(-1) = 2(-1) = -2 \]
05
Identify which function to use for f(0)
For \( f(0) \), note that \( 0 > -1 \). This means we use the second function \( f(x) = x - 1 \) for \( x > -1 \).
06
Calculate f(0)
Substitute \( x = 0 \) into the equation of the second function \( f(x) = x - 1 \):\[ f(0) = 0 - 1 = -1 \]
07
Identify which function to use for f(3)
For \( f(3) \), observe that \( 3 > -1 \). Therefore, we choose the second function \( f(x) = x - 1 \) where \( x > -1 \).
08
Calculate f(3)
Substitute \( x = 3 \) into the second function \( f(x) = x - 1 \):\[ f(3) = 3 - 1 = 2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Evaluating Functions
Evaluating functions involves determining the output of a function given a specific input. In this context, we're dealing with a piecewise function, meaning it has different expressions based on the value of the input variable, \(x\). A crucial first step is to identify which part of the piecewise function to use, according to the input value.
Take, for instance, the input \(-5\). Here, the condition \(x \leq -1\) applies, which directs us to use the function \(f(x) = 2x\). By substituting \(x = -5\) into this equation, we compute \(f(-5)\) as follows:
Take, for instance, the input \(-5\). Here, the condition \(x \leq -1\) applies, which directs us to use the function \(f(x) = 2x\). By substituting \(x = -5\) into this equation, we compute \(f(-5)\) as follows:
- \[ f(-5) = 2(-5) = -10 \]
Algebra Problems
Algebra problems often include piecewise functions as a practical application of different algebraic rules. Understanding these functions is essential for solving equations that switch expressions under various conditions.
Piecewise functions provide a great platform to apply basic algebra skills—addition, subtraction, multiplication, and division—by stipulating concise scenarios.
For example, let's determine \(f(-1)\) for the piecewise function:\[ \begin{align*} f(x) & = 2x && x \leq -1 \ & = x - 1 && x > -1 \end{align*} \]
Piecewise functions provide a great platform to apply basic algebra skills—addition, subtraction, multiplication, and division—by stipulating concise scenarios.
For example, let's determine \(f(-1)\) for the piecewise function:\[ \begin{align*} f(x) & = 2x && x \leq -1 \ & = x - 1 && x > -1 \end{align*} \]
- Since \(-1 \leq -1\), we use the first rule, \(f(x) = 2x\). Solving this gives:
\[ f(-1) = 2(-1) = -2 \]
Function Notation
Function notation is a way to convey information about functions clearly and precisely. In mathematics, a function is often expressed using symbols like \(f(x)\), where "f" denotes the function and "x" represents the variable or input.
When we write \(f(x) = 2x\), we denote that the output of the function \(f\) depends on the input \(x\), and is calculated as twice the input value. Function notation is not just about naming; it also helps in evaluating functions by emphasizing variable roles and relationships.
Consider \(f(0)\). Here, zero is substituted into the function expression valid under the appropriate conditions.
When we write \(f(x) = 2x\), we denote that the output of the function \(f\) depends on the input \(x\), and is calculated as twice the input value. Function notation is not just about naming; it also helps in evaluating functions by emphasizing variable roles and relationships.
Consider \(f(0)\). Here, zero is substituted into the function expression valid under the appropriate conditions.
- Since \(0 > -1\), we employ the second part of the piecewise function \(f(x) = x - 1\). Calculating this leads to:
\[ f(0) = 0 - 1 = -1 \]