Chapter 1: Problem 12
Work each problem related to linear functions. (a) Evaluate \(f(-2)\) and \(f(4)\) (b) Graph \(f\). How can the graph of \(f\) be used to determine the zero of \(f ?\) (c) Find the zero of \(f\) $$f(x)=\frac{1}{4} x+\frac{1}{2}$$
Short Answer
Expert verified
(a) \(f(-2) = 0, f(4) = \frac{3}{2}\). (b) Use the line to find the x-intercept (zero). (c) Zero is \(x = -2\).
Step by step solution
01
Evaluate f(-2) and f(4)
First, we need to substitute the given values into the function to find the desired outputs. To evaluate \(f(-2)\), substitute \(-2\) into the equation as follows:\[f(-2) = \frac{1}{4} (-2) + \frac{1}{2} = -\frac{1}{2} + \frac{1}{2} = 0\]Next, evaluate \(f(4)\) by substituting \(4\) into the equation:\[f(4) = \frac{1}{4} (4) + \frac{1}{2} = 1 + \frac{1}{2} = \frac{3}{2}\]Thus, \(f(-2) = 0\) and \(f(4) = \frac{3}{2}\).
02
Graph f(x) = (1/4)x + (1/2)
To graph the function \(f(x)=\frac{1}{4}x+\frac{1}{2}\), we start by plotting the y-intercept, which is \((0, \frac{1}{2})\). Next, use the slope, which is \(\frac{1}{4}\), indicating a rise of 1 unit for every 4 units run to plot another point starting from the y-intercept. For example, the point \((4, \frac{3}{2})\) can be used, as calculated previously.Draw a straight line through these points to represent the function. The zero of the function is where the line crosses the x-axis.
03
Use the Graph to Determine the Zero
The zero of a function corresponds to the x-value where the function crosses the x-axis (i.e., \(f(x) = 0\)). From the graph of \(f(x) = \frac{1}{4}x + \frac{1}{2}\), we can see the function crosses the x-axis at \(x = -2\). This confirms our previous finding that \(f(-2) = 0\).
04
Algebraically Find the Zero
Set the function equal to zero to determine the x-value where the function crosses the x-axis.\[0 = \frac{1}{4}x + \frac{1}{2}\]Subtract \(\frac{1}{2}\) from both sides:\[-\frac{1}{2} = \frac{1}{4}x\]Multiply both sides by \(4\) to solve for \(x\):\[x = -2\]So, the zero of the function is indeed \(x = -2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Linear Equations
Graphing linear equations is an essential skill in understanding linear functions. A linear equation can be represented graphically as a straight line. The first step is to identify key components of the equation, mainly the slope and the y-intercept. For a linear function like \(f(x) = \frac{1}{4}x + \frac{1}{2}\), it's in the slope-intercept form, which we'll discuss in detail later on.
When graphing, start by plotting the y-intercept. For our function, the y-intercept is \((0, \frac{1}{2})\). This is the point where the line crosses the y-axis.
When graphing, start by plotting the y-intercept. For our function, the y-intercept is \((0, \frac{1}{2})\). This is the point where the line crosses the y-axis.
- Plot the y-intercept as your first point on the graph.
- Use the slope to plot additional points.
- Slope of \(\frac{1}{4}\) means rise of 1 unit for every 4 units of horizontal run.
Finding Function Zeros
Finding the zero of a function is like finding a treasure map's X mark. It's the point where the function crosses the x-axis, representing the solution where the function equals zero. For our function \(f(x) = \frac{1}{4}x + \frac{1}{2}\), the zero is the x-value where \(f(x) = 0\).
To find the zero graphically, look at where the line intersects the x-axis on the graph. In this case, it crosses at \(x = -2\). You can verify this zero algebraically by setting the function equal to zero and solving for \(x\).
To find the zero graphically, look at where the line intersects the x-axis on the graph. In this case, it crosses at \(x = -2\). You can verify this zero algebraically by setting the function equal to zero and solving for \(x\).
- Set \(f(x) = 0\): \(0 = \frac{1}{4}x + \frac{1}{2}\).
- Subtract \(\frac{1}{2}\) from both sides: \(-\frac{1}{2} = \frac{1}{4}x\).
- Multiply both sides by 4: \(x = -2\).
Slope-Intercept Form
The slope-intercept form of a linear equation is an accessible format for analyzing and graphing linear functions. It is written as \(y = mx + b\), where \(m\) is the slope, and \(b\) is the y-intercept. This form provides key information at first glance:
- The slope \(m\) determines the steepness and direction of the line. A positive slope means the line rises from left to right. A negative slope means it falls.
- The y-intercept \(b\) indicates where the line crosses the y-axis, which is straightforward to plot.