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In each of Problems 1 through 10 show that the sequence \(\left\\{f_{n}(x)\right\\}\) converges to \(f(x)\) for each \(x\) on \(I\) and determine whether or not the convergence is uniform. $$ f_{n}: x \rightarrow n x e^{-n x^{2}}, \quad f(x) \equiv 0, \quad I=\\{x: 0 \leqslant x \leqslant 1\\} $$

Short Answer

Expert verified
The sequence \( f_n(x) \) converges pointwise to \( f(x) \) for all \( x \) in \( I \), but the convergence is not uniform.

Step by step solution

01

Understanding the function and its limit

Consider the given sequence of functions \( f_n(x) = n x e^{-n x^{2}} \) and the function \( f(x) = 0 \) to which the sequence is said to converge. The interval over which convergence needs to be evaluated is \( I=[0, 1] \).
02

Determining pointwise convergence

To show pointwise convergence, we need to demonstrate that for each \( x \) in \( I \), \( f_n(x) \) approaches \( f(x) \) as \( n \) goes to infinity. Take the limit of \( f_n(x) \) as \( n \to \) infinity: \[\lim_{n \to \infty} n x e^{-n x^{2}} = 0\] for all \( x \), since the exponential term \( e^{-n x^{2}} \) grows faster than the linear term \( n x \) and drives the product to zero.
03

Investigating uniform convergence

Uniform convergence means that the sequence \( f_n(x) \) converges to \( f(x) \) at the same rate for all \( x \) in \( I \). To evaluate this, examine the maximum value of \( f_n \) on \( I \). Differentiate \( f_n \) with respect to \( x \):$$ \frac{d}{dx}(n x e^{-n x^{2}}) = n e^{-n x^{2}} - 2n^2 x^2 e^{-n x^{2}}$$Set it to zero to find critical points: \[ n e^{-n x^{2}}(1 - 2n x^2) = 0\]. The non-trivial solution is \( x = 1/\sqrt{2n} \) inside \( I \). Substitute this \( x \) back into \( f_n \) to find the maximum value \( M_n \) and take the limit:$$\lim_{n \to \infty} \sqrt{n} e^{-1/2}$$Since this limit does not converge to zero, the convergence is not uniform.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pointwise Convergence
Pointwise convergence is a fundamental concept within the field of real analysis, specifically when examining the behavior of sequences of functions. To put it simply, a sequence of functions \( \{f_n(x)\} \) is said to exhibit pointwise convergence to a function \( f(x) \) on a set \( I \) if, for each individual point \( x \) within that set, the values of \( f_n(x) \) get arbitrarily close to \( f(x) \) as \( n \), the index of the sequence, grows without bound.

Imagine standing at each point \( x \) on the interval \( I \) and watching the values of the sequence \( f_n(x) \) as \( n \) increases. If these values settle down to the value of \( f(x) \) at that specific point, and stay close to it as \( n \) continues to increase, then we have pointwise convergence at \( x \) on \( I \). Using the principle of pointwise convergence, the step by step solution shows that for the given sequence, regardless of which \( x \) you're standing at within the interval \( [0, 1] \), the sequence \( f_n(x) = nxe^{-nx^2} \) approaches the function \( f(x) = 0 \) as \( n \) becomes larger and larger. This is confirmed by evaluating the limit of \( f_n(x) \) as \( n \rightarrow \) infinity, which indeed equates to zero for all points on the interval.
Sequence of Functions
A sequence of functions can be best understood as a list of functions ordered by an index, commonly denoted by \( n \) that typically runs through the set of natural numbers. These functions are often related in some manner, creating a progression as \( n \) increases. In our specific exercise, we have a sequence defined by \( f_n: x \rightarrow n x e^{-n x^{2}} \) for each natural number \( n \).

When examining sequences of functions, we look at their behavior as \( n \) becomes large; what they approach (\

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