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Five men and 5 women are ranked according to their scores on an examination. Assume that no two scores are alike and all 10! possible rankings are equally likely. LetXdenote the highest ranking achieved by a woman. (For instance,X=1 if the top-ranked person is female.) FindP{X=i},i=1,2,3,,8,9,10

Short Answer

Expert verified

P(X)={1/2,5/18,5/36,5/84,5/252,1/252,0,0,0,0}for x=1,2,3...,10 respectively.

Step by step solution

01

Step 1:Given Information

The total number of paths of ranking 10 different scores is 10!. The number of ways a female can be ranked 1 is.

ways of choosing any one out of 5. ways of arranging the rest 9

P(X=1)=5C19P910P10=5.9!10!=12

02

Step 2:Explanation

The number of ways a female can be ranked 2 is,

Ways of female can be ranked 2 or less: ways that Ist male and female/5.Ways rest 8 are ranked.

P(X=2)=5P15C18P810P10=5.5.8!10!=518
03

Step 3:Explanation

P(X=3)=5P25C17P710P10=20.5.7!10!=536

04

Step 4:Explanation

P(X=4)=5P35C16P610P10=6056!10!=584

05

Step 5:Explanation

P(X=5)=5P45C15P510P10=120.5.5!10!=5252

06

Step 6:Explanation

P(X=6)=5P55C14P410P10=12054!10!=1252

07

Step 7:Explanation

There existing only5boys, the lower value of X can be 6

P(X>6)=0
08

Step 8:Final Answer

P(X)={1/2,5/18,5/36,5/84,5/252,1/252,0,0,0,0}for x=1,2,3,...10 respectively.

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