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Show that Xis a Poisson random variable with parameter λ, then

EXn=λE(X+1)n-1

Now use this result to compute EX3.

Short Answer

Expert verified

EX3=λ3+3λ2+λ

Step by step solution

01

Step 1: Given information

Given in the question thatXis a Poisson random variable with parameter λ, then E[Xn]=λE[(X+1)n−1]. We need to find E[X3]

02

Step 2: Explanation

Using the theorem about the mean of function of random variable,

we have that

EXn=∑k=0∞knλkk!e-λ=∑k=1∞knλkk!e-λ=λ∑k=1∞knλk-1k!e-λ

=λ∑k=1∞kn-1λk-1(k-1)!e-λ=λ∑k=0∞(k+1)n-1λkk!e-λ=λE(X+1)n-1

which had to be proved. Using that, we have that

EX3=λE(X+1)2=λEX2+2X+1=λEX2+2E(X)+1

Now, use that EX2=Var(X)+EX2=λ+λ2

and thatEX=λ,

so we have that the expression above is equal to

=λλ+λ2+2λ+1=λ3+3λ2+λ

03

Step 3:Final answer

EX3=λ3+3λ2+λ

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