/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 4.27 An insurance company writes a po... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An insurance company writes a policy to the effect that an amount of money Amust be paid if some event Eoccurs within a year. If the company estimates that Ewill occur within a year with probability p, what should it charge the customer in order that its expected profit will be 10 percent ofA ?

Short Answer

Expert verified

The insurance company should charge the customer an amount of A(p+0.1).

Step by step solution

01

Given information

An insurance company writes a policy to the effect that an amount of money A must be paid if some event E occurs within a year.

02

Explanation

Let Xbe a random variable that represents the amount to be paid to the customer.

X=0, â¶Ä…â¶Ä…â¶Ä…ifEdoes not occurA, â¶Ä…â¶Ä…â¶Ä…ifEoccurs

Since P(X=0)=PEc=1-pand P(X=A)=P(E)=p, the distribution of Xis

X~0A1-pp

and its expectation is

E[X]=(1-p)0+pA=pA

03

Final answer

Let's say that the company charges the customer an amount of money B. The profit is then B-X, so expected profit is E[B-X]=0.1A. By using additivity of expectation we have

E[B-X]=B-E[X]=B-pA=0.1A

which gives

B=A(p+0.1)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

LetXbe the winnings of a gambler. Let p(i)=P(X=i)and suppose that

p(0)=1/3;p(1)=p(-1)=13/55

p(2)=p(-2)=1/11;p(3)=p(-3)=1/165

Compute the conditional probability that the gambler wins i,i=1,2,3,given that he wins a positive amount.

To determine whether they have a certain disease, 100people are to have their blood tested. However, rather than testing each individual separately, it has been decided first to place the people into groups of 10. The blood samples of the 10people in each group will be pooled and analyzed together. If the test is negative, one test will suffice for the 10people, whereas if the test is positive, each of the 10people will also be individually tested and, in all, 11tests will be made on this group. Assume that the probability that a person has the disease isrole="math" localid="1646542351988" .1 for all people, independently of one another, and compute the expected number of tests necessary for each group. (Note that we are assuming that the pooled test will be positive if at least one person in the pool has the disease.)

Show how the derivation of the binomial probabilities P{X=i}=nipi(1-p)n-i,i=0,…,nleads to a proof of the binomial theorem (x+y)n=∑i=0nnixiyn-iwhen xand yare nonnegative.

Hint: Let p=xx+y.

An urn has n white and m black balls. Balls are randomly withdrawn, without replacement, until a total of k,k…nwhite balls have been withdrawn. The random variable Xequal to the total number of balls that are withdrawn is said to be a negative hypergeometric random variable.

(a) Explain how such a random variable differs from a negative binomial random variable.

(b) Find P{X=r}.

Hint for (b): In order for X=r to happen, what must be the results of the firstr−1 withdrawals?

Suppose that the random variable Xis equal to the number of hits obtained by a certain baseball player in his next 3at-bats. If P{X=1}=3,P{X=2}=2andP{X=0}=3P{X=3}, find E[X].

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.