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In Problem 7.70, suppose that the coin is tossed ntimes. Let Xdenote the number of heads that occur. Show that P{X=i}=1n+1i=0,1,…,n

Hint: Make use of the fact that,

∫01xa-1(1-x)b-1dx=(a-1)!(b-1)!(a+b-1)!

When aandb are positive integers.

Short Answer

Expert verified

It has been shown thatP{X=i}=1n+1;i=0,1,…,n

Step by step solution

01

Given Information

Number of times coins tossed =n

Number of heads occur=X

Use:∫01xa-1(1-x)b-1dx=(a-1)!(b-1)!(a+b-1)!

Positive integers=a,b

02

Explanation

X=Number of heads that occur

If coin is tossed ntimes then Xcan take value 0.1.2……,n

P[Headsoccur]=p~U(0,1)

P[X=i]=∫01nipi(1-p)n-idp;i=0,1,2,…,n

=n!(i)!(n−i)!∫01 pi(1−p)n−idp

=n!(i)!(n−i)!(i)!(n−i)!(n+1)!

Since

∫01xa-1(1-x)b-1dx=(a-1)!(b-1)!(a+b-1)!

∴P[X=i]=1n+1;i=0,1,2,…,n

03

Final Answer

Hence, it has been shown thatP{X=i}=1n+1;i=0,1,…,n

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