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Suppose that the expected number of accidents per week at an industrial plant is 5. Suppose also that the numbers of workers injured in each accident are independent random variables with a common mean of 2.5. If the number of workers injured in each accident is independent of the number of accidents that occur, compute the expected number of workers injured in a week .

Short Answer

Expert verified

E(NX)=12.5

Step by step solution

01

Given information

Given in the question that, .Suppose that the expected number of accidents per week at an industrial plant is 5. Suppose also that the numbers of workers injured in each accident are independent random variables with a common mean of 2.5.

02

Explanation

Let N= number of accidents to happen in seven days. Allow X=to number of workers injured in every mishap. The quantity of workers injured in accidents each week should be N×X. So we needs E[NX]

Since we know that Nand Xare independent, we know that

Cov(N,X)=E(NX)-E(N)E(X)=0

⇒E(NX)=E(N)E(X)=5×2.5=12.5

03

Final answer

The expected number of workers injured in a week isE(NX)=12.5

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Most popular questions from this chapter

Two envelopes, each containing a check, are placed in front of you. You are to choose one of the envelopes, open it, and see the amount of the check. At this point, either you can accept that amount or you can exchange it for the check in the unopened envelope. What should you do? Is it possible to devise a strategy that does better than just accepting the first envelope? Let Aand B, A<B, denote the (unknown) amounts of the checks and note that the strategy that randomly selects an envelope and always accepts its check has an expected return of (A+B)/2. Consider the following strategy: Let F(·)be any strictly increasing (that is, continuous) distribution function. Choose an envelope randomly and open it. If the discovered check has the value x, then accept it with probability F(x)and exchange it with probability 1−F(x).

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