/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.6.21 Suppose that W, the amount of mo... [FREE SOLUTION] | 91影视

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Suppose that W, the amount of moisture in the air on a given day, is a gamma random variable with parameters (t, 尾). That is, its density is f(w) = 尾e鈭捨瞱(尾w)t鈭1/(t), w > 0. Suppose also that given that W = w, the number of accidents during that day鈥攃all it N鈥攈as a Poisson distribution with mean w. Show that the conditional distribution of W given that N = n is the gamma distribution with parameters (t + n, 尾 + 1)

Short Answer

Expert verified

In order to obtain the required conditional distribution, use the definition of conditional PDF.

Step by step solution

01

Content Introduction

A random variable is a variable with an unknown value or a function that gives values to each of the results of an experiment. It's possible for a random variable to be discrete or continuous.

02

Content Explanation

We are required to find the distribution of W given that N = n. We have that,

fW,N(w,n)=fW,N(w,n)P(N=n)=P(N=n|W=w)fW(w)P(N=n)

Since, we have that N/W=w~Pois(w)we have that

P(N=n,W=w)=wnn!e-w

Thus,

P(N=n,W=w)fW(w)P(N=n)=wnn!e-w.e-w(w)t-1(t)P(N=n)

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