/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q:5.2 聽For some constant c, the rando... [FREE SOLUTION] | 91影视

91影视

For some constant c, the random variable X has the probability density function f(x) = c x n 0 < x < 1 0 otherwise Find (a) c and

(b) P{X > x}, 0 < x < 1.

Short Answer

Expert verified

The result is (a)c=n+1

(b)P(X>x)=1-xn+1

Step by step solution

01

Step:1 Given Information

Otherwise, the random variable X has the probability density function f(x)=cxn,0<x<10for some constant c. Find (a) c and(b)P{X>x},0<x<1.

02

Step:2 Definition

A probability density function (PDF) is used in probability theory to characterize the random variable's likelihood of falling into a specific range of values rather than taking on a single value. The function illustrates the normal distribution's probability density function and how mean and deviation are calculated.

03

Step:3 Explanation of the solution

(a) Condition must be met by the probability density function.

fdx=1

Hence, there has to be

1=f(x)dx=01cxndx=cxn+1n+101=cn+1

Finally, the c constant must equal n+1.

(b) Calculate the requisite probability as the integral of f over the suitable

region. That is something we have.

P(X>x)=x1f(s)ds=x1(n+1)snds=sn+1x1=1-xn+1

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.