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The speed of a molecule in a uniform gas at equilibrium is a random variable whose probability density function is given by

f(x)=ax2e−bx2x≥00x<0

whereb=m/2kTandmdenote, respectively,

Boltzmann’s constant, the absolute temperature of the gas,

and the mass of the molecule. Evaluate ain terms ofb.

Short Answer

Expert verified

Therefore ain terms ofbthena=4b32Ï€.

Step by step solution

01

Given Information.

f(x)=ax2e−bx2x≥00x<0

Where,

b=m/2kT

02

Explanation.

∫0∞f(x)dx=1∫0∞ax2e-bx2dx=1

localid="1649615141474" bx2=t2xdx=dt∫0∞ax2e-t×dt2bx=1

03

Explanation.

bx2=t⇒x2=tb⇒x=tba2b32∫0∞t12e-tdt=1a2b32×32=1aπ4b32=1a=4b32π

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