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The probability of the closing of the ith relay in the circuits shown in Figure 3.4 is given by pi,i=1,2,3,4,5. If all relays function independently, what is the probability that a current flows between A and B for the respective circuits?

Short Answer

Expert verified

a) The probability isp1p2+p3p4-p1p2p3p4p5

b)The probability is

p1p4+p2p5+p3p1p5+p2p4-p1p2p3p4+p1p2p3p5+p1p2p4p5+p1p3p4p5+p2p3p4p5+2p1p2p3p4p5

Step by step solution

01

Given Information(Part a)

Electrical circuit from Ato B

5independent switches

Ci- event that switch iis closed,

PCi=pi,i=1,2,3,4,5

P(E), the probability that the current flows.

02

Explanation (Part a)

We see that the current flows either through switches 1,2,5 or through 3,4,5. The first row uses the Inclusion and Exclusion formula and the second the independence

P(E)=PC1C2C5∪C3C4C5

=PC1C2C5+PC3C4C5-PC1C2C3C4C5

=PC1PC2PC5+PC3PC4PC5-PC1PC2PC3PC4PC5

=p1p2p5+p3p4p5-p1p2p3p4p5

=p1p2+p3p4-p1p2p3p4p5

03

Final Answer (Part a)

p1p2+p3p4-p1p2p3p4p5

04

Given Information (Part b)

Electrical circuit from Ato B

5independent switches

Ci- event that switch iis closed,

PCi=pi,i=1,2,3,4,5.
05

Explanation (Part b)

The current flows if 1 and 4 are closed or 2 and 5 are closed.

If the switch 3 is closed the current can flow also through switches $1,3,5$ or through 2,3,4.

P(E)=PC1C4∪C2C5∪C3C1C5∪C3C2C4

=PC3cC1C4∪C2C5∪C3C1C4∪C2C5∪C1C5∪C2C4

=PC3cPC1C4∪C2C5+PC3PC1C4∪C2C5∪C1C5∪C2C4

=p1p4+p2p5-p1p2p4p5+p1p2p3p4p5+p3p1p5+p2p4-p1p2p4-p1p2p5-p1p4p5-p2p4p5+p1p2p3p4p5

role="math" localid="1647859751713" =p1p4+p2p5+p3p1p5+p2p4-p1p2p3p4+p1p2p3p5+p1p2p4p5+p1p3p4p5+p2p3p4p5+2p1p2p3p4p5

06

Final Answer (Part b)

The probability is

p1p4+p2p5+p3p1p5+p2p4-p1p2p3p4+p1p2p3p5+p1p2p4p5+p1p3p4p5+p2p3p4p5+2p1p2p3p4p5

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