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Chapter 3: Q3.16 (page 98)

Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a C section is performed, the baby survives 96 percent of the time when a C section is performed, the baby survives 96 percent of the time . If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?

Short Answer

Expert verified

The probability that a randomly chosen pregnant woman does not have a C section, is that her baby survives is 0.9835

Step by step solution

01

Given Information

Given that ninety-eight percent of all babies survive delivery.

15 percent of all births involve Cesarean (C) sections,

when a C section is performed, the baby survives 96 percent of the time

We have to find the probability that a baby survives at randomly chosen pregnant women does not have a C section,

02

Explanation

Diagram

Decision Tree Analysis

03

Explanation of Diagram

C : Cesarian delivery,CC: Normal delivery,S: Survival,D: Death

P(S)=0.15脳0.96+0.85脳x

P(S)=0.98 given

0.98=0.15x0.96+0.85xx

鈬�x=0.9835

04

Ste 4  Final Answer

The probability that a randomly chosen pregnant woman does not have a C section, is that her baby survives is 0.9835

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