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(a) Prove that if Eand Fare mutually exclusive, then

localid="1647926638131" P(EEF)=P(E)P(E)+P(F)

(b) Prove that if localid="1647926673038" Ei,i1are mutually exclusive, then

localid="1648539605315" PEji=1Ei=PEji=1PEi

Short Answer

Expert verified

We concluded that

(a) If Eand Fare mutually exclusive then P(EEF)=P(E)P(E)+P(F)

(b) IfEi,i1are mutually exclusive thenPEji=1Ei=PEji=1PEi.

Step by step solution

01

Concept Introduction Part(a)

Mutually exclusive is a statistical word defining two or more possibilities that cannot occur simultaneously. It is normally used to represent a case where the happening of one output replaces the other.

02

Explanation Part(a)

If Eand Fare mutally exclusive then EF=.

Since E(EF)=Eand by aditivity P(EF)=P(E)+P(F),

we conclude that

P(EEF)=P(E(EF))P(EF)

=P(E)P(E)+P(F).

03

Final Answer Part(a)

P(EEF)=P(E(EF))P(EF)=P(E)P(E)+P(F)

04

Concept Introduction Part(b)

Mutually exclusive is a statistical word defining two or more possibilities that cannot occur simultaneously. It is normally used to represent a case where the happening of one output replaces the other.

05

Explanation Part (b)

Since

Eji=1Ei=i=1EjEi=ijEjEi==Ej

Pi=1Ei=[-aditivity/Axiom3]=i=1PEi

We concluded that

PEji=1Ei=PEji=1EiPi=1Ei

=PEji=1PEi.

06

Final Answer Part(b)

PEji=1Ei=PEji=1EiPi=1Ei=PEji=1PEi

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