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If 4Americans, 3French people, and 3British people are to be seated in a row, how many seating arrangements are possible when people of the same nationality must sit next to each other?

Short Answer

Expert verified

The required no. of seating arrangements are5184.

Step by step solution

01

Step 1. Given information.

It is given that,

No. of Americans =4

No. of French =3

No. of British =3

All these people are to be seated in a row.

02

Step 2. Find the required no. of seating arrangements.

Three groups can be arranged in=3!ways=3×2×1=6ways

Four Americans can be arranged in = 4!ways=4×3×2×1=24ways

Three French can be arranged in =3!ways=3×2×1=6ways

Three British can be arranged in =3!ways=3×2×1=6ways

Total no. of waysrole="math" localid="1648406231161" =6×24×6×6=5184

Therefore, the required no. of seating arrangements are5184.

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