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An ordinary deck of52cards is shuffled. What is the probability that the top four cards have

(a) different denominations?

(b) different suits?

Short Answer

Expert verified

a)P(the four cards have different denominations)=134·44524≈0.67611.

b)P(the four cards are of different suits)=134524≈0.1055.

Step by step solution

01

Given Information.

An ordinary deck of52cards is shuffled.

02

Explanation.

The described experiment is equivalent to:

Experiment: Four random cards are drawn from a standard 52card deck.

Outcome spaceScontains every combination of cards.

If all events Sare considered equally likely, the probability of an event A⊆Sis:

P(A)=|A||S|

In the chapter1.4. it is shown that the number of four card combinations of52different cards is524=|S|.

03

Part (a) Explanation.

P(the four cards have different denominations)

Count all possible events from Swhere four cards have different denominations, using the basic principle (the product principle)

Then each of the cards can be in any of the four colors. Total of 44different possibilities.

There are 134·44elements in the event where all denominations of cards are different.

P(the four cards have different denominations)=134·44524≈0.67611

04

Part (b) Explanation.

P(the four cards are of different suits)

Count all possible events from Swhere four cards are of different suits, using the basic principle (the product principle)

First choose the four suits, in one way.

Then each of the cards in some suit can be in any of the thirteen cards. Total of 134different possibilities.

There are 134elements in the event where all denominations of cards are different.

P(the four cards are of different suits)=134524≈0.1055

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