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A random variable can take on any of n possible values x1, ... , xn with respective probabilities p(xi), i = 1, ... , n. We shall attempt to determine the value of X by asking a series of questions, each of which can be answered 鈥測es鈥 or 鈥渘o.鈥 For instance, we may ask 鈥淚s X = x1?鈥 or 鈥淚s X equal to either x1 or x2 or x3?鈥 and so on. What can you say about the average number of such questions that you will need to ask to determine the value of X?

Short Answer

Expert verified

The average number of questions to determine the value of XisEX-n2n

Step by step solution

01

Given Information

We have to find the average number of questions that you will need to ask to determine the value of X.

02

Simplify

Mark that the answer to a particular question is 12i.e.

PYes=PNo=12

which meansPX=k=12kfor k=1,,n. So, the average number of questions is

localid="1648130867761" EX=k=1nk12k

To calculate, multiply it by 12.

localid="1648130836360" 12EX=k=1nk12k+1

Subtracting that from the expression in 1, we have that

localid="1648130797034" 12EX=k=1nk12k+1-n.12n+1

Using the formula localid="1648133543693" k=1n12k=12.1-0.5n+11-0.5to obtain that the final answer. That is

EX-n2n

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