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A man claims to have extrasensory perception. As a test, a fair coin is flipped 10 times and the man is asked to predict the outcome in advance. He gets 7 out of 10 correct. What is the probability that he would have done at least this well if he had no ESP?

Short Answer

Expert verified
The probability of the man correctly predicting the outcome of a fair coin flip at least 7 out of 10 times without ESP is 0.1719 (or 17.19%).

Step by step solution

01

Calculate the probability of exactly 7 correct predictions.

Using the binomial probability formula, we have: \(P(X=7) = C(10,7) * 0.5^7 * (1-0.5)^{10-7}\) \(P(X=7) = \frac{10!}{7!(10-7)!} * 0.5^7 * 0.5^3\) \(P(X=7) = 120 * 0.5^7 * 0.5^3 = 0.1172\)
02

Calculate the probability of exactly 8 correct predictions.

Using the binomial probability formula, we have: \(P(X=8) = C(10,8) * 0.5^8 * (1-0.5)^{10-8}\) \(P(X=8) = \frac{10!}{8!(10-8)!} * 0.5^8 * 0.5^2\) \(P(X=8) = 45 * 0.5^8 * 0.5^2 = 0.0439\)
03

Calculate the probability of exactly 9 correct predictions.

Using the binomial probability formula, we have: \(P(X=9) = C(10,9) * 0.5^9 * (1-0.5)^{10-9}\) \(P(X=9) = \frac{10!}{9!(10-9)!} * 0.5^9 * 0.5^1\) \(P(X=9) = 10 * 0.5^9 * 0.5^1 = 0.0098\)
04

Calculate the probability of exactly 10 correct predictions.

Using the binomial probability formula, we have: \(P(X=10) = C(10,10) * 0.5^{10} * (1-0.5)^{10-10}\) \(P(X=10) = \frac{10!}{10!(10-10)!} * 0.5^{10} * 0.5^0\) \(P(X=10) = 1 * 0.5^{10} * 1 = 0.00098\)
05

Calculate the probability of at least 7 correct predictions.

To find the probability of at least 7 correct predictions out of 10, we need to sum the probabilities we just calculated: \(P(X \ge 7) = P(X=7) + P(X=8) + P(X=9) + P(X=10)\) \(P(X \ge 7) = 0.1172 + 0.0439 + 0.0098 + 0.00098\) \(P(X \ge 7) = 0.1719\) So, the probability of the man correctly predicting the outcome of a fair coin flip at least 7 out of 10 times without ESP is 0.1719 (or 17.19%).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability Theory
At its core, probability theory is all about measuring the likelihood of events. Whether you're flipping a coin or predicting the weather, probability theory helps you understand the odds of different outcomes. It is based on the premise of a probability space that includes all possible outcomes and assigns a probability to each of these outcomes.
The fundamentals include concepts like events (which are outcomes or sets of outcomes) and probability (a number between 0 and 1 indicating how likely an event is to occur). For a fair coin, there is a 50% chance it will land heads and a 50% chance it will land tails every time you flip it. This basic framework allows you to calculate the chance of more complex occurrences including sequences of independent events.
The Binomial Probability Formula
The binomial probability formula is used in situations where there are repeated trials of a binary event. Binary events have only two possible outcomes—like flipping a coin, where you can get either heads or tails. This formula helps calculate the probability of obtaining a specific number of successes in a fixed number of trials.
The formula is given by: \[ P(X = k) = C(n, k) \cdot p^k \cdot (1-p)^{n-k} \] where:
  • \( P(X = k) \) is the probability of \( k \) successes in \( n \) trials.
  • \( C(n, k) \) is a binomial coefficient, representing the number of ways to choose \( k \) events out of \( n \).
  • \( p \) is the probability of success on each trial.
  • \( (1-p) \) is the probability of failure.
This structure is utilized to solve the original problem by determining the likelihood that our man could correctly predict a certain number of coin flips.
Diving into Combinatorics
Combinatorics involves counting, arranging, and finding patterns within sets of items. It plays a significant role in calculating the binomial coefficient used in binomial probability formulas.
In terms of the binomial coefficient \( C(n, k) \), this represents the number of combinations of \( n \) items taken \( k \) at a time.
It is calculated using the formula:\[ C(n, k) = \frac{n!}{k!(n-k)!} \]where \( n! \) (pronounced \( n \)-factorial) is simply the product of all positive integers up to \( n \).
For example, to find \( C(10, 7) \) when predicting outcomes from 10 coin flips and getting 7 correct, you solve:\[ C(10, 7) = \frac{10!}{7! \cdot 3!} \ = 120 \] This part of combinatorics helps us understand the different ways of achieving certain results.
Understanding Cumulative Probability
Cumulative probability refers to the probability of obtaining a certain number of successes or fewer. Alternatively, it can also mean at least a certain number of successes. It's used in our problem to calculate the total probability of achieving at least a certain number of correct predictions.
The cumulative probability is found by adding the probabilities of each individual event from that threshold onwards. Based on the calculations:\[ P(X \geq 7) = P(X=7) + P(X=8) + P(X=9) + P(X=10) \]
Each of these probabilities represents a scenario where he correctly guesses the outcome 7, 8, 9, or all 10 times.
In our example, this total is 0.1719, representing a 17.19% chance that the man could make at least 7 correct predictions. This concept helps in aggregating probabilities to assess overall odds of an event occurring.

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Most popular questions from this chapter

The number of times that a person contracts a cold in a given year is a Poisson random variable with parameter \(\lambda=5 .\) Suppose that a new wonder drug (based on large quantities of vitamin \(\mathrm{C}\) ) has just been marketed that reduces the Poisson parameter to \(\lambda=3\) for 75 percent of the population. For the other 25 percent of the population, the drug has no appreciable effect on colds. If an individual tries the drug for a year and has 2 colds in that time, how likely is it that the drug is beneficial for him or her?

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