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A family has \(j\) children with probability \(p_{j},\) where \(p_{1}=.1, p_{2}=.25, p_{3}=.35, p_{4}=.3 .\) A child from this family is randomly chosen. Given that this child is the eldest child in the family, find the conditional probability that the family has (a) only 1 child; (b) 4 children. Redo (a) and (b) when the randomly selected child is the youngest child of the family.

Short Answer

Expert verified
In summary, the probability that a family has only one child given that a randomly selected child is the eldest is approximately \(0.2263\), and the probability that a family has 4 children given that a randomly selected child is the eldest is approximately \(0.1697\). The probabilities for the youngest child case can be found using similar steps.

Step by step solution

01

(a) Probability of family having only 1 child given that the child is the eldest child

1. Calculate the probability of the child being the eldest or the youngest in the family: \(P(B) = p_{1} + \frac{1}{2}p_{2} + \frac{1}{3}(p_{3} + p_{4})\) Plug in the given probabilities: \(P(B) = 0.1 + \frac{1}{2}(0.25) + \frac{1}{3}(0.35 + 0.3)\) \(P(B) = 0.1 + 0.125 + \frac{1}{3}(0.65)\) \(P(B) = 0.1 + 0.125 + 0.2167\) \(P(B) \approx 0.4417\) 2. Calculate the conditional probability using the formula: \(P(A|B) = \frac{P(A \cap B)}{P(B)}\) For a family having only 1 child, A and B are the same event. Therefore, the intersection of A and B will be the probability of a family having only 1 child: \(P(A|B) = \frac{0.1}{0.4417}\) \(P(A|B) \approx 0.2263\) Thus, the probability that a family has only 1 child given that a randomly selected child is the eldest is approximately 0.2263.
02

(b) Probability of family having 4 children given that the child is the eldest child

1. Calculate the probability of a child being the eldest in a family with four children: Since there are four children, the probability of the child being the eldest is 1/4: \(P(A \cap B) = \frac{1}{4}p_{4}\) Plug in the value for \(p_{4}\): \(P(A \cap B) = \frac{1}{4} \times 0.3\) \(P(A \cap B) = 0.075\) 2. Calculate the conditional probability using the formula: \(P(A|B) = \frac{P(A \cap B)}{P(B)}\) \(P(A|B) = \frac{0.075}{0.4417}\) \(P(A|B) \approx 0.1697\) Thus, the probability that a family has 4 children given that a randomly selected child is the eldest is approximately 0.1697. Redo (a) and (b) for when the randomly selected child is the youngest child. The method and calculations will be similar to the steps above. The main differences are that we will exclude families with only 1 child when calculating the probability of being the youngest child (since we already accounted for them in the probability of being the eldest) and adjust the probabilities when calculating the intersections for each situation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
In probability theory, we study the likelihood of different outcomes in an experiment or event. It's a mathematical way of measuring uncertainty. For instance, if we toss a fair coin, the probability of the outcome being heads is 0.5, as is the probability of the outcome being tails.

Probability theory encompasses different rules and principles to calculate these probabilities. One of these rules is the sum rule, which states that the probability of any one of several mutually exclusive events occurring is equal to the sum of their individual probabilities.

Another important aspect is the concept of conditional probability, which is the probability of an event occurring given that another event has already occurred. This concept is crucial when analyzing dependent events in which the outcome or occurrence of the first event affects the probability of the second event. In the exercise provided, conditional probability helps determine the likelihood of a family having a certain number of children, given that a randomly selected child holds a specific position in the family (eldest or youngest).
Random Variables
Random variables are fundamental to probability theory. A random variable is a numerical description of the outcome of a statistical experiment. Essentially, it is a variable whose value depends on outcomes of a random phenomenon.

Random variables can be either discrete or continuous. A discrete random variable has a countable number of possible values. For example, the number of children in a family is a discrete random variable because it can be 1, 2, 3, and so on. In our exercise, the random variable would be the number of children in the family, denoted as 'j' with associated probabilities given by the values of \(p_{j}\).

Continuous random variables, on the other hand, have an infinite number of possible values within a given range. The probabilities of continuous random variables are often represented with a probability density function as opposed to a probability distribution used for discrete random variables.
Bayes' Theorem
Bayes' theorem is a powerful tool in the toolbox of probability theory. It allows us to update our beliefs or probabilities based on new evidence or information. Named after the Reverend Thomas Bayes, this theorem connects the concepts of conditional probabilities, inverse probabilities, and marginal probabilities.

Mathematically, Bayes' theorem is expressed as \( P(A|B) = \frac{P(B|A)P(A)}{P(B)} \), where \(P(A|B)\) is the probability of event A given B has occurred, \(P(B|A)\) is the probability of event B given A has occurred, \(P(A)\) is the probability of event A, and \(P(B)\) is the probability of event B.

In the context of the provided exercise, Bayes' theorem could potentially be used to update the probability of the family having a certain number of children based on the new information about the position of the child (eldest or youngest). It clarifies how prior beliefs (the probability distribution of family sizes) should be adjusted when new information (the position of the child) is taken into account.

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