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If two dice are rolled, what is the probability that the sum of the upturned faces equals \(i ?\) Find it for \(i=2,3, \ldots, 11,12\).

Short Answer

Expert verified
The probability of the sum of upturned faces being equal to $i$ when rolling two dice is as follows: \(i = 2: \frac{1}{36}\) \(i = 3: \frac{1}{18}\) \(i = 4: \frac{1}{12}\) \(i = 5: \frac{1}{9}\) \(i = 6: \frac{5}{36}\) \(i = 7: \frac{1}{6}\) \(i = 8: \frac{5}{36}\) \(i = 9: \frac{1}{9}\) \(i = 10: \frac{1}{12}\) \(i = 11: \frac{1}{18}\) \(i = 12: \frac{1}{36}\)

Step by step solution

01

List the possible outcomes of rolling two dice

The total number of possible outcomes when rolling two dice is 36 since each die has 6 faces, and we have a combination of these faces for each die. Here are all the possible outcomes: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
02

Count the number of successful outcomes for each sum

Now, we will go through the possible sums, i, and count the number of occurrences of each sum in the list of outcomes: i = 2: (1, 1) - 1 outcome i = 3: (1, 2), (2, 1) - 2 outcomes i = 4: (1, 3), (2, 2), (3, 1) - 3 outcomes i = 5: (1, 4), (2, 3), (3, 2), (4, 1) - 4 outcomes i = 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) - 5 outcomes i = 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) - 6 outcomes i = 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) - 5 outcomes i = 9: (3, 6), (4, 5), (5, 4), (6, 3) - 4 outcomes i = 10: (4, 6), (5, 5), (6, 4) - 3 outcomes i = 11: (5, 6), (6, 5) - 2 outcomes i = 12: (6, 6) - 1 outcome
03

Calculate the probability for each sum

Now that we have the number of successful outcomes for each sum, we can calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes (36): i = 2: 1/36 i = 3: 2/36 i = 4: 3/36 i = 5: 4/36 i = 6: 5/36 i = 7: 6/36 i = 8: 5/36 i = 9: 4/36 i = 10: 3/36 i = 11: 2/36 i = 12: 1/36 As a final step, we can simplify these fractions: i = 2: 1/36 i = 3: 1/18 i = 4: 1/12 i = 5: 1/9 i = 6: 5/36 i = 7: 1/6 i = 8: 5/36 i = 9: 1/9 i = 10: 1/12 i = 11: 1/18 i = 12: 1/36

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
In the context of probability, a random variable is a numerical outcome of a random phenomenon. For our problem involving two dice, a random variable could represent the sum of the numbers shown on the dice when they are rolled. This sum ranges from 2 to 12.

Random variables can be discrete or continuous. In this dice scenario, the sum of the dice is a discrete random variable since it can only take on certain finite values (i.e., the integers between 2 and 12).

More generally, when you analyze different problems, you will often define different random variables to capture various aspects of the randomness involved. Understanding random variables is a fundamental step in analyzing any probabilistic system, as they allow us to model and make predictions about the phenomena we are studying.
Combinatorics
Combinatorics is a branch of mathematics that explores counting, arrangement, and combination of elements within a set. It is essential in this scenario, as it helps us enumerate all possible outcomes when rolling two dice.

To solve our problem, combinatorics informed us that each die has 6 faces. Thus, rolling two dice gives us a total of 6 × 6 = 36 possible outcomes. We list combinations like (1,1), (1,2), ..., (6,6) to visualize all potential results.

Understanding combinatorics is not only about listing possibilities but also about systematically counting these possibilities. This allows us to calculate probabilities accurately, as knowing the universe of possibilities is crucial to determining the frequency of successful events. Mastering this concept is particularly useful across various probability problems.
Probability Distribution
A probability distribution describes how probabilities are distributed over the possible values of a random variable. In this two-dice roll scenario, the probability distribution tells us the likelihood of each possible sum (from 2 to 12).

We calculated the probability of obtaining each sum by counting how often each occurs in our list of outcomes. For example, there is only one way to get a sum of 2 (by rolling 1 on both dice), resulting in a probability of \( \frac{1}{36} \). This distribution can graphically display probabilities along the x-axis (with sums from 2 to 12) and probabilities on the y-axis.

Such distributions help visualize and understand how likely different outcomes are. They are a powerful tool for analyzing random events, allowing us to derive insights into expected outcomes and variability. Recognizing different types of probability distributions is vital in fields ranging from data science to finance.

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