/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A fair die is rolled 10 times. C... [FREE SOLUTION] | 91Ó°ÊÓ

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A fair die is rolled 10 times. Calculate the expected sum of the 10 rolls.

Short Answer

Expert verified
The expected sum of rolling a fair die 10 times is 35.

Step by step solution

01

Determine the expected value of a single die roll

To find the expected value of a die roll, we must multiply each possible outcome by its probability and sum the results. The probability of each number appearing is the same, which is 1/6. Expected value of a single roll, denoted as E(X): \(E(X) = 1* \frac{1}{6} + 2* \frac{1}{6} + 3* \frac{1}{6} + 4* \frac{1}{6} + 5* \frac{1}{6} + 6* \frac{1}{6}\)
02

Calculate the expected value of a single die roll

Now, we'll calculate the expected value of a single roll: \(E(X) = \frac{1}{6}\left(1+2+3+4+5+6\right)\) \(E(X) = \frac{1}{6}(21)\) \(E(X) = 3.5\) So the expected value of a single roll is 3.5. This means that, on average, we expect the result of a die roll to be 3.5.
03

Determine the expected sum for 10 die rolls

The expected sum for 10 die rolls is the expected value of a single roll multiplied by the number of rolls. Since the rolls are independent, we can directly calculate the expected sum: Expected sum = \(E(X) * \textrm{number of rolls}\)
04

Calculate the expected sum

Now, we'll calculate the expected sum for the 10 die rolls: Expected sum = \(3.5 * 10\) Expected sum = 35 The expected sum of rolling a fair die 10 times is 35.

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