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A couple has 2 children. What is the probability that both are girls if the eldest is a girl?

Short Answer

Expert verified
The probability that both children are girls, given that the eldest is a girl, is \(\frac{1}{2}\) or 50%.

Step by step solution

01

List the possible outcomes given the condition

We need to list the possible outcomes of the 2 children. But since we know the eldest is a girl, the only possible outcomes are Girl-Girl (GG) and Girl-Boy (GB).
02

Calculate the total number of outcomes

There are two possible outcomes: (GG) and (GB). So, the total number of outcomes is 2.
03

Determine the number of successful outcomes

The successful outcome we're looking for is both children being girls (GG). There is only 1 successful outcome.
04

Calculate the probability

To calculate the probability, we will divide the number of successful outcomes by the total number of outcomes. Probability = \(\frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}}\) Probability = \(\frac{1}{2}\) So, the probability that both children are girls, given that the eldest is a girl, is \(\frac{1}{2}\) or 50%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
When we talk about conditional probability, we are referring to the likelihood of an event occurring given that another event has already taken place. It helps us update our predictions about outcomes by factoring in new information. In our example, the condition is that one of the children, specifically the eldest, is a girl. This fact changes the scope of possible outcomes we need to consider when calculating the probability of the event 'both children are girls'.

To calculate conditional probability, we use the formula:
\[\begin{equation}P(A|B) = \frac{P(A \text{ and } B)}{P(B)}\end{equation}\]
where:
  • P(A|B) represents the probability of event A given event B has occurred.
  • P(A and B) refers to the probability of both A and B occurring together.
  • P(B) indicates the probability of event B occurring.
In the exercise, since we know that the eldest is a girl, P(B) is 1 because that event has a 100% chance of having occurred. The 'A and B' scenario and event A both coincide since they represent the same event: both children being girls. Therefore, we do not need to calculate P(A and B) separately. This simplifies our calculation significantly.
Probability Outcomes
Understanding probability outcomes is essential for grasping various probability problems. Outcomes are the possible results that can occur from a random process, and when working with probabilities, it's important to identify all possible outcomes to perform accurate calculations. In our example problem, there are initially four potential outcomes when a couple has two children: Boy-Boy (BB), Boy-Girl (BG), Girl-Boy (GB), and Girl-Girl (GG).

However, since the condition is that the eldest is a girl, we exclude the Boy-Boy (BB) and Boy-Girl (BG) outcomes. This leaves us with just two outcomes: Girl-Boy (GB) and Girl-Girl (GG). This reduction of possible scenarios is a direct application of incorporating given conditions into our probability assessment, thus simplifying the problem and guiding us towards the correct solution.
Probability Calculation
The final step in solving probability questions is the actual calculation. Probability calculation requires dividing the number of successful outcomes by the total number of possible outcomes. Using an analogy, imagine you have a bag of marbles with different colors. If you want to determine the probability of pulling out a red marble, you need to know the total number of red marbles and compare that to the overall total number of marbles in the bag.

We apply this same logic to our problem. As previously mentioned, after considering the condition that the eldest child is a girl, we have only two possible outcomes: Girl-Boy (GB) and Girl-Girl (GG). Since we're interested in the scenario where both are girls, only one outcome—Girl-Girl (GG)—is favorable. Therefore, the probability calculation is straightforward:
\[\begin{equation}Probability = \frac{1 \text{ (number of successful outcomes)}}{2 \text{ (total number of outcomes)}} = \frac{1}{2}\end{equation}\]
Understanding and executing these calculations are crucial for determining the likelihood of certain events and for making informed decisions based on probability.

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Most popular questions from this chapter

\(A\) and \(B\) are involved in a duel. The rules of the duel are that they are to pick up their guns and shoot at each other simultaneously. If one or both are hit, then the duel is over. If both shots miss, then they repeat the process. Suppose that the results of the shots are independent and that each shot of \(A\) will hit \(B\) with probability \(p_{A}\), and each shot of \(B\) will hit \(A\) with probability \(p_{B}\). What is (a) the probability that \(A\) is not hit; (b) the probability that both duelists are hit; (c) the probability that the duel ends after the \(n\)th round of shots; (d) the conditional probability that the duel ends after the \(n\)th round of shots given that \(A\) is not hit; (e) the conditional probability that the duel ends after the \(n\)th round of shots given that both duelists are hit?

\(A\) and \(B\) flip coins. A starts and continues flipping until a tail occurs. At this point \(B\) starts flipping and continues until there is a tail, then \(A\) takes over, and so on. Let \(P_{1}\) be the probability of the coin's landing heads when \(A\) flips, and \(P_{2}\) when \(B\) flips. The winner of the game is the first one to get (a) 2 heads in a row; (b) a total of 2 heads; (c) 3 heads in a row; (d) a total of 3 heads. In each case, find the probability that \(A\) wins.

If \(A\) flips \(n+1\) and \(B\) flips \(n\) fair coins, show that the probability that \(A\) gets more heads than \(B\) is \(\frac{1}{2}\). HINT: Condition on which player has more heads after each has flipped \(n\) coins. (There are three possibilities.)

Die \(A\) has 4 red and 2 white faces, whereas die \(B\) has 2 red and 4 white faces. A fair coin is flipped once. If it lands on heads, the game continues with die \(A\); if it lands tails, then die \(B\) is to be used. (a) Show that the probability of red at any throw is \(\frac{1}{2}\).

(a) A gambler has in his pocket a fair coin and a two-headed coin. He selects one of the coins at random; when he flips it, it shows heads. What is the probability that it is the fair coin? (b) Suppose that he flips the same coin a second time and again it shows heads. What is now the probability that it is the fair coin? (c) Suppose that he flips the same coin a third time and it shows tails. What is now the probability that it is the fair coin?

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