Chapter 2: Problem 6
Show that the polynomial ring \(F[X, Y]\) in two variables over a field is not a Euclidean domain.
Short Answer
Expert verified
The polynomial ring \(F[X, Y]\) is not a Euclidean domain because polynomials such as \(X\) and \(Y\) do not satisfy the division algorithm condition.
Step by step solution
01
Understanding Euclidean Domains
A Euclidean domain is an integral domain equipped with a Euclidean function (or valuation) \(u\) that allows for a form of the division algorithm. Specifically, for any two elements \(a, b eq 0\) in the domain, there exist elements \(q\) and \(r\) such that \((a = bq + r)\), where either \(r = 0\) or \(u(r) < u(b)\).
02
Polynomial Ring in Two Variables
Consider the polynomial ring \(F[X, Y]\) in two variables over a field \(F\). Elements of \(F[X, Y]\) are polynomials in the variables \(X\) and \(Y\) with coefficients from \(F\).
03
Select Polynomials to Test Division Algorithm
Select two polynomials \(f = X\) and \(g = Y\) in \(F[X, Y]\).
04
Attempt Division
Assume we attempt to write \(X = Yq + r\) for some \(q\) and \(r\) in \(F[X, Y]\). Because \(X\) has degree 1 in \(X\) and degree 0 in \(Y\), and \(Y\) has degree 1 in \(Y\) and degree 0 in \(X\), it's impossible to find such \(q\) and \(r\) where \(r = 0\) or \(u(r) < u(Y)\), since \(r\) in this context would have to be a polynomial in \(X\).
05
Conclusion
Since there is no suitable division satisfying the Euclidean algorithm for \(f = X\) and \(g = Y\), the polynomial ring \(F[X, Y]\) does not meet the criteria to be a Euclidean domain.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Ring
Let's first understand what a polynomial ring is. A polynomial ring, denoted as \( F[X, Y] \), is a set of polynomials in two variables, \( X \) and \( Y \), with coefficients from a field \( F \). Each element of \( F[X, Y] \) is a finite sum of the form:
\( a_{ij} X^i Y^j \),
where \( i \) and \( j \) are non-negative integers, and \( a_{ij} \) are coefficients from \( F \). Here are some key points about polynomial rings:
\( a_{ij} X^i Y^j \),
where \( i \) and \( j \) are non-negative integers, and \( a_{ij} \) are coefficients from \( F \). Here are some key points about polynomial rings:
- Polynomials can be added and multiplied to form new polynomials, staying within the ring.
- Each polynomial has a degree, which is the sum of the degrees of \( X \) and \( Y \).
- The degree of a polynomial can be complex when it contains more than one variable.
Integral Domain
An integral domain is a type of ring where the multiplication of any two non-zero elements is never zero. In simpler terms, if \( a \) and \( b \) are elements of an integral domain, and if \( a \times b = 0 \), then either \( a = 0 \) or \( b = 0 \).
Key properties of integral domains include:
Key properties of integral domains include:
- No zero divisors: This is a fancy way of saying that you can't multiply two non-zero elements and get zero.
- Commutativity: The multiplication of elements is commutative, meaning \( a \times b = b \times a \).
- Multiplicative identity: There exists an element, typically denoted as 1, such that \( a \times 1 = a \) for any element \( a \) in the domain.
Division Algorithm
The division algorithm is a principle that ensures division with a remainder in algebra. In the context of Euclidean domains, it states that for any two elements \( a \) and \( b \) (where \( b e 0 \) ), there are unique elements \( q \) and \( r \) in the domain such that:
\( a = bq + r \),
with \( r = 0 \) or \( u(r) < u(b) \). Here, \( u \) is a Euclidean function assigning a non-negative integer to each element of the domain.
Now let's apply this to the polynomial ring \( F[X, Y] \):
Suppose we try to divide \( X \) by \( Y \). We want to find polynomials \( q \) and \( r \) in \( F[X, Y] \) such that:
\( X = Yq + r \).
Given \( \text{deg}(X) = 1 \) and \( \text{deg}(Y) = 1 \), finding such \( q \) and \( r \) becomes complex. The remainder \( r \) must have a degree lower than \( Y \). However, it is impossible to define \( r \) in such a way that \( r = 0 \) or \( \text{deg}(r) < \text{deg}(Y) \), making the polynomial ring \( F[X, Y] \) non-Euclidean. This conclusion shows that not all polynomial rings possess the properties needed to meet the criteria of a Euclidean domain, highlighting the importance of the division algorithm.
\( a = bq + r \),
with \( r = 0 \) or \( u(r) < u(b) \). Here, \( u \) is a Euclidean function assigning a non-negative integer to each element of the domain.
Now let's apply this to the polynomial ring \( F[X, Y] \):
Suppose we try to divide \( X \) by \( Y \). We want to find polynomials \( q \) and \( r \) in \( F[X, Y] \) such that:
\( X = Yq + r \).
Given \( \text{deg}(X) = 1 \) and \( \text{deg}(Y) = 1 \), finding such \( q \) and \( r \) becomes complex. The remainder \( r \) must have a degree lower than \( Y \). However, it is impossible to define \( r \) in such a way that \( r = 0 \) or \( \text{deg}(r) < \text{deg}(Y) \), making the polynomial ring \( F[X, Y] \) non-Euclidean. This conclusion shows that not all polynomial rings possess the properties needed to meet the criteria of a Euclidean domain, highlighting the importance of the division algorithm.