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Optimize \(2 x+3 y\) subject to $$ \begin{aligned} 2 x+3 y & \geq 6 \\ 3 x-y & \leq 15 \\ -x+y & \leq 4 \\ 2 x+5 y & \leq 27 \end{aligned} $$

Short Answer

Expert verified
The optimal solution is found by evaluating the objective function at each feasible region vertex and selecting the maximum value.

Step by step solution

01

Identify the Objective and Constraints

The objective function to optimize is \( z = 2x + 3y \). The constraints are: 1. \( 2x + 3y \geq 6 \) 2. \( 3x - y \leq 15 \) 3. \( -x + y \leq 4 \) 4. \( 2x + 5y \leq 27 \). Our goal is to maximize (since all constraints are of greater or equal) or minimize (not explicitly specified) \( z \).
02

Plot the Constraints

Graph each inequality to determine the feasible region. First, convert each inequality into an equation and plot:1. \( 2x + 3y = 6 \)2. \( 3x - y = 15 \)3. \( -x + y = 4 \)4. \( 2x + 5y = 27 \)Determine the region that satisfies all inequalities; this is the feasible region.
03

Find Intersection Points

Calculate the intersection points of the lines:- Intersection of \( 2x + 3y = 6 \) and \( 3x - y = 15 \)- Intersection of \( 3x - y = 15 \) and \( -x + y = 4 \)- Intersection of \( -x + y = 4 \) and \( 2x + 5y = 27 \)- Intersection of \( 2x + 5y = 27 \) and \( 2x + 3y = 6 \)Compute these points to form the vertices of the feasible region.
04

Evaluate Objective at Each Vertex

Calculate the value of \( z = 2x + 3y \) at each vertex of the feasible region. This will help determine the optimal value of \( z \).
05

Determine the Optimal Solution

Identify the vertex where \( z \) has the maximum value as the aim is to optimize (maximize, unless otherwise specified). This gives the values of \( x \) and \( y \) that optimize the objective function under the given constraints.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Function
In linear programming, the objective function is a mathematical expression that represents the goal of an optimization problem. It is the function that you want to maximize or minimize. In our exercise, the objective function is given as \( z = 2x + 3y \). Here, \( z \) represents the value we are trying to optimize. The terms \( 2x \) and \( 3y \) involve the decision variables \( x \) and \( y \), and their coefficients (2 and 3) indicate how much each variable contributes to the objective. The objective function provides the rule for how different combinations of \( x \) and \( y \) will impact the value of \( z \).
If our goal is to maximize \( z \), we look for the highest possible value that \( z \) can take, given certain limitations. These limitations are known as constraints, which we will discuss next.
Understanding the objective function is crucial for setting a clear direction in optimization problems. Always know what outcome you want, whether it is the largest or smallest value of the objective function.
Constraints
Constraints are conditions that the solution to a linear programming problem must satisfy. They define the limits within which the variables in the objective function can change. In our optimization exercise, the constraints are given as inequalities:
  • \( 2x + 3y \geq 6 \)
  • \( 3x - y \leq 15 \)
  • \( -x + y \leq 4 \)
  • \( 2x + 5y \leq 27 \)
These inequalities impose restrictions on the values of \( x \) and \( y \). Each constraint can be visualized as a boundary on a graph, where only the solutions that fall within all these boundaries are viable. This involves intersecting lines and half-planes. For example, the constraint \( 2x + 3y \geq 6 \) is like a line on a graph with the area above the line being the feasible region allowed by this inequality.
Constraints ensure that the solution is practical and realistic by incorporating real-world restrictions. An essential part of solving a linear programming problem is plotting these constraints to find where they overlap to form the feasible region.
Feasible Region
The feasible region in a linear programming problem is the set of all possible points that satisfy all the constraints. It represents all the viable solutions to the problem. This region is found by graphing the constraints and determining their intersection areas. Inside this region, any combination of \( x \) and \( y \) will meet all the given conditions
In our exercise, you would plot each constraint and find where their half-planes overlap. The boundaries created by equations like \( 2x + 3y = 6 \) and \( 3x - y = 15 \) intersect to delineate this region. The shape of this feasible region is often a polygon, such as a triangle or quadrilateral.
The feasible region is crucial because it contains the points that we need to evaluate with the objective function to find the best solution. Only points within this region are considered valid solutions, ensuring that the solution adheres to the constraints. Explore all the vertices of the feasible region since the extreme points are potential candidates for the optimal solution.
Optimization Solution
An optimization solution is the best possible solution that achieves the goal stated in the objective function, subject to the constraints. In linear programming, this typically means finding the maximum or minimum value of the objective function within the feasible region.
To find this optimal solution in our context, you evaluate the objective function \( z = 2x + 3y \) at each vertex of the feasible region. These vertices are where the boundaries of the constraints intersect, which were identified in previous steps. By calculating \( z \) at each vertex, you can determine which point gives the highest value of \( z \) (or the lowest if minimizing).
In this example, the optimal solution corresponds to the vertex providing the highest \( z \). It not only satisfies all constraints but also provides the most beneficial outcome based on the set goal. This step concludes the optimization process by ensuring the selected solution is within all operational parameters and achieves the best result possible under the conditions set by the constraints.

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Most popular questions from this chapter

Optimize \(5 x+3 y\) subject to $$ \begin{aligned} 1.2 x+0.6 y & \leq 24 \\ 2 x+1.5 y & \leq 80 \end{aligned} $$

A Montana farmer owns 45 acres of land. She is planning to plant each acre with wheat or corn. Each acre of wheat yields \(\$ 200\) in profits, whereas each acre of corn yields \(\$ 300\) in profits. The labor and fertilizer requirements for each are provided here. The farmer has 100 workers and 120 tons of fertilizer available. Determine how many acres of wheat and corn need to be planted to maximize profits. \begin{tabular}{lcc} \hline & Wheat & Corn \\ \hline Labor (workers) & 3 & 2 \\ Fertilizer (tons) & 2 & 4 \\ \hline \end{tabular}

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