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Find two power series solutions of the given differential equation about the ordinary point \(x=0\). $$y^{\prime \prime}-(x+1) y^{\prime}-y=0$$

Short Answer

Expert verified
Use the assumed series solutions to solve the differential equation as a power series expansion about \(x=0\).

Step by step solution

01

Identify the Form of Power Series Solutions

Since the differential equation involves powers of \(x\), we assume a power series solution of the form \(y(x) = \sum_{n=0}^{fty} a_n x^n\). We will also find the derivatives: \(y'(x) = \sum_{n=1}^{fty} n a_n x^{n-1}\) and \(y''(x) = \sum_{n=2}^{fty} n(n-1) a_n x^{n-2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation
A differential equation is a mathematical equation that relates some function with its derivatives. In the given problem, the differential equation is \[ y''(x)-(x+1)y'(x)-y(x)=0 \] This equation describes a relationship between the function \( y(x) \), its first derivative \( y'(x) \), and its second derivative \( y''(x) \). The task is to find a solution for this equation, which can often describe physical phenomena like motion, growth, or decay in real-world problems.

To solve this differential equation, we need to look for solutions that can be expressed in special forms, like power series, which allows manipulations and easier calculations. Understanding differential equations is crucial in fields ranging from engineering to physics and economics.
Ordinary Point
An ordinary point in the context of differential equations refers to a point where the equation does not exhibit any mathematical singularity. In other words, it’s a point at which the coefficients of the differential equation are well-defined and finite. In the problem, the equation is presented about the ordinary point \( x = 0 \).

This means at \( x = 0 \), the function and its derivatives involved in the differential equation remain smooth and well-behaved. Being an ordinary point ensures that we can proceed with finding solutions using methods like power series, avoiding complications that would arise at singular points. This makes solving the differential equation more straightforward.
Derivatives
Derivatives are mathematical tools that measure how a function changes as its input changes. In the equation \[ y''(x) - (x+1)y'(x) - y(x) = 0 \]we see both the first derivative \( y'(x) \) and the second derivative \( y''(x) \).

To use a power series to solve the differential equation, we must find expressions for these derivatives in series form as well. The series expressions are:
  • For \( y(x) = \sum_{n=0}^{\infty} a_n x^n \)
  • First derivative: \( y'(x) = \sum_{n=1}^{\infty} n a_n x^{n-1} \)
  • Second derivative: \( y''(x) = \sum_{n=2}^{\infty} n(n-1) a_n x^{n-2} \)
These series allow us to substitute into the original differential equation and find a solution by matching coefficients. This approach is particularly useful when looking for solutions around ordinary points.
Assume a Power Series Solution
Assuming a power series solution is a strategy used to tackle differential equations, particularly when the solutions are expected to be smooth functions. For the given problem, the strategy involves expressing \( y(x) \) as a power series:

\[ y(x) = \sum_{n=0}^{\infty} a_n x^n \]

This approach is potent because it breaks down complex calculations into simpler algebraic manipulations of coefficients \( a_n \). The power series representation allows us to express \( y(x) \), \( y'(x) \), and \( y''(x) \) in forms that are easy to differentiate and integrate.

By substituting these series into the differential equation, one can systematically determine the coefficients \( a_n \) by matching terms. This method can find unique or multiple solutions, which are sums representing \( y(x) \) around the ordinary point. Thus, assuming a power series solution is a cornerstone technique in differential equation analysis, providing a clear pathway to complex problems.

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Most popular questions from this chapter

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. $$\left(x^{2}+x-6\right) y^{\prime \prime}+(x+3) y^{\prime}+(x-2) y=0$$

Use (1) to find the general solution of the given differential equation on \((0, \infty)\). $$4 x^{2} y^{\prime \prime}+4 x y^{\prime}+\left(4 x^{2}-25\right) y=0$$

A uniform thin column of length \(L,\) positioned vertically with one end embedded in the ground, will deflect, or bend away, from the vertical under the influence of its own weight when its length or height exceeds a certain critical value. It can be shown that the angular deflection \(\theta(x)\) of the column from the vertical at a point \(P(x)\) is a solution of the boundary-value problem: $$E I \frac{d^{2} \theta}{d x^{2}}+\delta g(L-x) \theta=0, \quad \theta(0)=0, \quad \theta^{\prime}(L)=0$$ where \(E\) is Young's modulus, \(I\) is the cross-sectional moment of inertia, \(\delta\) is the constant linear density, and \(x\) is the distance along the column measured from its base. See Figure 6.4 .7 The column will bend only for those values of \(L\) for which the boundary-value problem has a nontrivial solution. (a) Restate the boundary- value problem by making the change of variables \(t=L-x\). Then use the results of a problem earlier in this exercise set to express the general solution of the differential equation in terms of Bessel functions. (b) Use the general solution found in part (a) to find a solution of the BVP and an equation which defines the critical length \(L\), that is, the smallest value of \(L\) for which the column will start to bend. (c) With the aid of a CAS, find the critical length \(L\) of a solid steel rod of radius \(r=0.05\) in., \(\delta g=0.28 A\) lb/in. \(E=2.6 \times 10^{7} \mathrm{lb} / \mathrm{in.}^{2}, A=\pi r^{2},\) and \(I=\frac{1}{4} \pi r^{4}\)

Use a substitution to shift the summation index so that the general term of given power series involves \(x^{k}\). $$\sum_{n=3}^{\infty}(2 n-1) c_{n} x^{n-3}$$

Find the interval and radius of convergence for the given power series. $$\sum_{n=1}^{\infty} \frac{2^{n}}{n} x^{n}$$

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