Chapter 6: Problem 13
Use an appropriate series in (2) to find the Maclaurin series of the given function. Write your answer in summation notation. $$\frac{1}{2+x}$$
Short Answer
Expert verified
The Maclaurin series of \(\frac{1}{2+x}\) is \(\sum_{n=0}^{\infty} (-1)^n \frac{x^n}{2^{n+1}}\).
Step by step solution
01
Identify the Series to Use
The goal is to find the Maclaurin series for the function \(f(x) = \frac{1}{2 + x}\). This function resembles the geometric series \(\frac{1}{1-x} = \sum_{n=0}^{\infty} x^n\). However, we need to adjust it to fit \(f(x)\).
02
Rewrite Function for Series Expansion
To express \(f(x)\) in a form suitable for a series expansion similar to the geometric series, rewrite it as \(\frac{1}{2(1 + \frac{x}{2})}\). This simplification highlights that \(f(x)\) is a transformed geometric series.
03
Apply Geometric Series to Transformed Function
Recognize that \(\frac{1}{1+ \frac{x}{2}}\) can be expanded as a geometric series: \(\sum_{n=0}^{\infty} \left(-\frac{x}{2}\right)^n\). Therefore, our function is \(\frac{1}{2} \cdot \sum_{n=0}^{\infty} \left(-\frac{x}{2}\right)^n\).
04
Simplify the Series Expression
Distribute the \(\frac{1}{2}\) throughout the series: \(\sum_{n=0}^{\infty} \frac{1}{2} \left(-\frac{x}{2}\right)^n = \sum_{n=0}^{\infty} (-1)^n \frac{x^n}{2^{n+1}}\). This is the Maclaurin series of \(\frac{1}{2+x}\) in summation notation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a series with a constant ratio between successive terms. The most basic form of a geometric series is given by the expression: \( \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \). This formula proves incredibly useful since it simplifies the process of expressing functions as infinite sums.
For a geometric series:
For a geometric series:
- The first term is always constant, typically 1 in this form.
- The common ratio is denoted by \( x \) in the formula.
- Every term after the first one is obtained by multiplying the preceding term by \( x \).
Series Expansion
Series expansion is the process of expressing a function as a sum of terms of a sequence, usually infinite. This concept is crucial in analysis and calculus because it allows us to approximate functions and continue working with them in simpler forms.
- It helps in evaluating complicated functions by expressing them as simpler, infinite polynomials.
- It allows for the comparison of functions and convergence analysis by simplifying calculations.
Summation Notation
Summation notation is a concise way to express the sum of a series of terms that follow a specific pattern. It uses the Greek letter sigma (\(\Sigma\)) to denote the operation of adding a set of terms based on a defining rule, typically conveyed in terms of an index variable.
- It provides a neat, organized means of expressing long sums that follow distinct mathematical rules over a specified range.
- The expression under the summation sign represents the pattern or rule of the series, such as \( (-1)^n \frac{x^n}{2^{n+1}} \).
- The notation often includes limits of summation, showing the range over which the index variable changes, usually from 0 to infinity for infinite series.