/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Consider the differential equati... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the differential equation \(y^{\prime}=y^{2}+4\) (a) Explain why there exist no constant solutions of the DE. (b) Describe the graph of a solution \(y=\phi(x)\). For example, can a solution curve have any relative extrema?

Short Answer

Expert verified
No constant solutions exist, and the solution curve has no relative extrema.

Step by step solution

01

Understanding Constant Solutions

A constant solution to a differential equation is where the derivative of the function doesn't change, i.e., \( y' = 0 \). For the given equation \( y' = y^2 + 4 \), setting \( y' = 0 \) implies \( y^2 + 4 = 0 \). However, since \( y^2 \) is always non-negative for any real \( y \), \( y^2 + 4 \) will never equal 0. Thus, there are no constant solutions.
02

Analyzing Extrema of the Solution

A relative extremum (maximum or minimum) of a curve occurs where the derivative of the function is zero. Therefore, for an extremum, we need \( y' = 0 \), which translates to \( y^2 + 4 = 0 \). As derived earlier, this is impossible. Therefore, the solution curve \( y = \phi(x) \) has no relative extrema.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Solutions in Differential Equations
A constant solution in the context of differential equations means that the function remains unchanged over time. This essentially leads to the derivative of the function being zero. For the differential equation given, which is \( y' = y^2 + 4 \), we are asked if there could be a constant solution. To determine this, we set \( y' = 0 \). This implies \( y^2 + 4 = 0 \). However, if you think about it, \( y^2 \) represents the square of a real number, which is always zero or positive—never negative, zero at the least. Thus, adding any non-zero positive value, such as 4, will always give a positive result, never zero. Consequently, \( y^2 + 4 = 0 \) has no real solutions, meaning there are no constant solutions possible for the differential equation \( y' = y^2 + 4 \).
  • No constant value of \( y \) can satisfy the equation.
  • The sum of a non-negative number and 4 cannot equal zero.
Relative Extrema in Solution Graphs
The concept of relative extrema is closely related to the behavior of a function's graph. They occur where the slope of the tangent to the curve—represented by the derivative—is zero. In other words, these points are where the graph reaches a local maximum or minimum. For the equation \( y' = y^2 + 4 \), we previously explained that \( y' \) can never be zero due to the nature of \( y^2 + 4 \) being always positive for real numbers. This absence of zero in the derivative means no flattening of the curve occurs anywhere. Therefore, the function doesn't possess relative maxima or minima.
  • Relies on \( y' = 0 \) to identify extrema.
  • Never zero, hence no relative extrema in the graph of \( y = \phi(x) \).
Graph Analysis of Differential Solutions
Analyzing the behavior of a solution's graph from a differential equation can provide insights into the nature of the function across a range of input values. Differential equations frequently inform us how quickly or slowly a solution changes. In the case of \( y' = y^2 + 4 \), since \( y' \) is always positive, it indicates that as \( x \) increases or decreases, \( y \) will generally move upward, continuously increasing. This is because the derivative does not change sign to indicate any downtrend; it remains positive, indicating a strictly increasing function for all real \( y \). Consider the following:
  • Derivative \( y' \) always positive suggests a rising solution.
  • No zero derivative, implying no peaks or valleys—steady increase only.
  • The lack of constant solutions implies the graph is never steady.
Understanding graph behavior is crucial when discussing the dynamics that differential equations describe.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the concept that \(y=c,-\infty < x < \infty,\) is a constant function if and only if \(y^{\prime}=0\) to determine whether the given differential equation possesses constant solutions. $$y^{\prime \prime}+4 y^{\prime}+6 y=10$$

\(y=c_{1} \cos 2 x+c_{2} \sin 2 x\) is a two-parameter family of solutions of the second-order DE \(y^{\prime \prime}+4 y=0 .\) If possible, find a solution of the differential equation that satisfies the given side conditions. The conditions specified at two different points are called boundary conditions. $$y^{\prime}(\pi / 2)=1, y^{\prime}(\pi)=0$$

Verify that the indicated family of functions is a solution of the given differential equation. Assume an appropriate interval \(I\) of definition for each solution. $$\frac{d^{2} y}{d x^{2}}-4 \frac{d y}{d x}+4 y=0 ; \quad y=c_{1} e^{2 x}+c_{2} x e^{2 x}$$

Use a CAS to compute all derivatives and to carry out the simplifications needed to verify that the indicated function is a particular solution of the given differential equation. $$\begin{aligned} &x^{3} y^{\prime \prime \prime}+2 x^{2} y^{\prime \prime}+20 x y^{\prime}-78 y=0\\\ &y=20 \frac{\cos (5 \ln x)}{x}-3 \frac{\sin (5 \ln x)}{x} \end{aligned}$$

Population Model The differential equation \(\frac{d P}{d t}=(k \cos t) P\) where \(k\) is a positive constant, is a model of human population \(P(t)\) of a certain community. Discuss an interpretation for the solution of this equation. In other words, what kind of population do you think the differential equation describes?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.