Chapter 1: Problem 42
Verify that the indicated pair of functions is a solution of the given system of differential equations on the interval \((-\infty, \infty)\). $$\begin{aligned} &\frac{d^{2} x}{d t^{2}}=4 y+e^{t}\\\ &\frac{d^{2} y}{d t^{2}}=4 x-e^{t}\\\ &\begin{array}{l} x=\cos 2 t+\sin 2 t+\frac{1}{5} e^{t} \\ y=-\cos 2 t-\sin 2 t-\frac{1}{5} e^{t} \end{array} \end{aligned}$$
Short Answer
Step by step solution
Write the System of Equations
Find First Derivatives
Find Second Derivatives
Substitute into the Differential Equations
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
System of Differential Equations
- \( \frac{d^2 x}{dt^2} = 4y + e^t \)
- \( \frac{d^2 y}{dt^2} = 4x - e^t \)
Second Derivative
- For \( x(t) = \cos 2t + \sin 2t + \frac{1}{5}e^t \), the second derivative is \( \frac{d^2 x}{dt^2} = -4\cos 2t - 4\sin 2t + \frac{1}{5}e^t \).
- Similarly, for \( y(t) = -\cos 2t - \sin 2t - \frac{1}{5}e^t \), the second derivative is \( \frac{d^2 y}{dt^2} = 4\cos 2t + 4\sin 2t - \frac{1}{5}e^t \).
Verification of Solutions
- Substitute \( y(t) \) into \( 4y + e^t \) to check the first equation; we find that \( 4(-\cos 2t - \sin 2t - \frac{1}{5}e^t) + e^t = -4\cos 2t - 4\sin 2t + \frac{1}{5}e^t \), which aligns with \( \frac{d^2 x}{dt^2} \).
- Similarly, for the second equation, substituting \( x(t) \) into \( 4x - e^t \) results in \( 4(\cos 2t + \sin 2t + \frac{1}{5}e^t) - e^t = 4\cos 2t + 4\sin 2t - \frac{1}{5}e^t \), matching \( \frac{d^2 y}{dt^2} \).
Mathematical Modeling
- The variable \( x(t) \) might represent displacement, voltage, or some other quantity of interest.
- The variable \( y(t) \) could represent a related property, influenced by changes in \( x(t) \).