Chapter 5: Problem 9
Evaluate the given integral along the indicated contour. \(\int_{C}\left(x^{2}+i y^{3}\right) d z\), where \(C\) is the straight line from \(z=1\) to \(z=i\)
Short Answer
Expert verified
The integral evaluates to \(-\frac{7}{12} + \frac{i}{3}\).
Step by step solution
01
Parametrize the Contour
The contour is a straight line from \(z=1\) to \(z=i\). We can parametrize this line using \(z(t) = 1 + t(i - 1)\), where \(t\) ranges from 0 to 1. Thus, \(z(t) = 1 - t + it\).
02
Differentiate the Parametrization
Calculate \(\frac{dz}{dt}\) from the parametrization. We have \(z(t) = 1 - t + it\), so the derivative \(\frac{dz}{dt} = -1 + i\).
03
Express x and y in Terms of t
From \(z(t) = 1 - t + it\), we identify \(x = 1 - t\) and \(y = t\).
04
Substitute into the Integral
Substitute \(x = 1 - t\) and \(y = t\) into the integrand \(x^2 + iy^3\). This gives \((1-t)^2 + i(t)^3\).
05
Set Up the Integral
The integral becomes \(\int_{0}^{1} ((1-t)^2 + it^3)(-1+i)\, dt\).
06
Simplify the Expression
Expand \(((1-t)^2 + it^3)(-1+i)\) to simplify the integrand: - The real part becomes - \(-((1-t)^2) + it^3\).- The imaginary part expands to \(-i(1-t)^2 + it^3 (-1 + i)\).
07
Integrate the Real and Imaginary Parts
Separate the real part and imaginary part for integration. Integrate the real part \(-((1-t)^2)\) and the imaginary part \(i(t^3 - (1-t)^2)\) from 0 to 1. - Calculate \(\int_{0}^{1} -(1-t)^2 \,dt \).- Calculate \(\int_{0}^{1} i(t^3 - (1-t)^2)\, dt\).
08
Evaluate the Integrals
Evaluate both integrals with respect to \(t\) over the interval from 0 to 1.- Real part integral: Integrate to get \(- \frac{1}{3}\). - Imaginary part integral: Integrate and evaluate to get \(- \frac{1}{4} + \frac{i}{3}\).
09
Combine Results
Add the real and imaginary parts: \(- \frac{1}{3} + (- \frac{1}{4} + \frac{i}{3})\). Combine like terms to get the final answer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Contour Integration
Contour integration is a powerful technique used in complex analysis to evaluate integrals along a path, or contour, in the complex plane. It is especially useful for integrals involving complex functions, where real number techniques might not work effectively. The main objective is to integrate a complex function over a designated contour, which could be a line, curve, or any closed shape.
Key points about contour integration include:
Key points about contour integration include:
- It allows for integration along paths in the complex plane, providing a way to handle complex functions directly.
- Contour can be any path in the complex plane, including straight lines, arcs, or even more complex curves.
- Integrating along a contour often involves parametrizing the contour and substituting into the integral.
Parametrization
Parametrization is a method of expressing the contours or curves in terms of a parameter, typically denoted by \(t\). This parameter ranges over some interval, allowing the contour to be traced precisely in the complex plane.
Here's how parametrization works:
Here's how parametrization works:
- Choose a parameter \(t\), which defines a path \(z(t)\) along the contour.
- Express variables \(x\) and \(y\) in terms of \(t\), which links the contour to a specific path in the complex plane.
- The derivative \(\frac{dz}{dt}\) is then calculated to aid in integration.
Complex Integrals
Complex integrals extend the concepts of integrating real-valued functions to those of complex-valued functions. In these integrals, both the integration path (contour) and the function's values are complex numbers, which introduces unique challenges and benefits.
Important characteristics of complex integrals include:
Important characteristics of complex integrals include:
- Both the real and imaginary parts of the function may need to be integrated separately.
- Complex integrals are often simplified by transforming the integral into a real one through substitution and parametrization.
- The result of these integrals is equally complex, consisting of real and imaginary components.