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Express the given function \(f\) in the form \(f(z)=u(x, y)+i v(x, y)\). \(f(z)=e^{-i z}\)

Short Answer

Expert verified
The function is expressed as \( f(z) = \cos(x)e^{-y} - i \sin(x)e^{-y} \).

Step by step solution

01

Identify Complex Components

The function provided is \( f(z) = e^{-iz} \), where \( z = x + iy \). Since \( z \) is a complex number, we need to express it in terms of its real and imaginary components, \( x \) and \( y \), so continue by substituting \( z = x + iy \) into the function.
02

Substitute and Simplify

Substituting the expression \( z = x + iy \) into the function, we have:\[ f(z) = e^{-i(x + iy)} = e^{-ix + y}. \] Next, observe how the expression can be simplified using exponent properties as follows: \[ f(z) = e^{-ix} \cdot e^{-y}. \]
03

Rewrite Using Euler's Formula

Using Euler's formula, \( e^{-ix} = \cos(-x) + i\sin(-x) = \cos(x) - i\sin(x) \). Substitute this into the simplified expression:\[ f(z) = (\cos(x) - i\sin(x)) \cdot e^{-y}. \]
04

Separate Real and Imaginary Parts

Distribute the \( e^{-y} \) to both parts of the expression:\[ f(z) = \cos(x)e^{-y} - i \sin(x)e^{-y}. \] The real part \( u(x, y) \) is \( \cos(x)e^{-y} \) and the imaginary part \( v(x, y) \) is \( - \sin(x)e^{-y} \).
05

Express Function in Required Form

Combine the real and imaginary components to express the function in the form \( f(z) = u(x, y) + iv(x, y) \):\[ f(z) = \cos(x)e^{-y} + i(-\sin(x)e^{-y}). \] Therefore, \( u(x, y) = \cos(x)e^{-y} \) and \( v(x, y) = -\sin(x)e^{-y} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Euler's Formula
Euler's formula is a beautiful equation in mathematics that connects exponential functions to trigonometric functions. It is expressed as \( e^{ix} = \cos(x) + i\sin(x) \). This formula shows how complex exponentials can be represented using sine and cosine. It's a vital tool when working with complex numbers and functions, such as in the exercise you are working on.

When you see a complex exponential like \( e^{-ix} \), you can use Euler's formula to rewrite it. For example:
  • \( e^{-ix} = \cos(-x) + i\sin(-x) \)
  • Since \( \cos(-x) = \cos(x) \) and \( \sin(-x) = -\sin(x) \), we get \( e^{-ix} = \cos(x) - i\sin(x) \)
Using Euler's formula allows us to easily separate a complex expression into real and imaginary parts, which is necessary for further calculations. It’s a straightforward yet powerful concept in complex analysis.
Real and Imaginary Parts
In complex analysis, any complex number can be expressed as a combination of a real part and an imaginary part. This is essential when transforming complex functions into the desired form \( f(z) = u(x, y) + iv(x, y) \).

The exercise asks you to identify these parts in the expression \( f(z) = e^{-iz} \). By using Euler's formula, the expression becomes \( (\cos(x) - i\sin(x)) \cdot e^{-y} \). Now we can separate the components:
  • The **real part** \( u(x, y) \) is \( \cos(x)e^{-y} \)
  • The **imaginary part** \( v(x, y) \) is \( -\sin(x)e^{-y} \)
These parts allow us to express the complex function with real-world implications, turning abstract math into something more concrete and understandable. This separation is a fundamental step in complex function analysis.
Exponential Function
The exponential function is a key concept in mathematics, often expressed as \( e^{z} \) where \( e \) is Euler's number, approximately 2.71828. In the context of complex numbers, it takes a unique role, combining shifts, rotations, and scalings in a complex plane.

In the exercise, you deal with \( e^{-iz} \) which involves properties of both real numbers and exponentials. To simplify such expressions:
  • First, substitute the complex variable \( z = x + iy \) into the function
  • This results in \( e^{-i(x + iy)} = e^{-ix + y} \)
  • The expression can be split using the property: \( e^{a+b} = e^{a} \cdot e^{b} \), translating to \( e^{-ix} \cdot e^{-y} \)
Understanding the properties of the exponential function helps in breaking down complex expressions into more manageable parts. Coupled with Euler’s formula, this simplification breaks the problem into a combination of trigonometric representations and exponential decays. This approach is very effective when analyzing or solving complex equations.

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