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In Problems \(33-36\), find all complex values of \(z\) satisfying the given equation. \(e^{1 / z}=-1\)

Short Answer

Expert verified
The general solution is \(z = \frac{i}{\pi (1 + 4k^2)}\) for any integer \(k\).

Step by step solution

01

Understand the Equation

The given equation is \(e^{1/z} = -1\). We need to find all complex numbers \(z\) that satisfy this equation. Recall that \(-1\) is equivalent to \(e^{i\pi + 2k\pi i}\) for any integer \(k\). This gives us multiple possible solutions for \(1/z\).
02

Solve for \(1/z\) in Exponential Form

Write \(-1\) in its exponential form: \(-1 = e^{i\pi + 2k\pi i}\), where \(k\) is an integer. Equate this to \(e^{1/z}\) to get: \(1/z = i\pi + 2k\pi i\).
03

Express \(z\) in Terms of \(k\)

To find \(z\), take the reciprocal: \(z = \frac{1}{i\pi + 2k\pi i}\).
04

Simplify \(z\)

Simplify \(z\) using the conjugate of the denominator. Multiply the numerator and the denominator by the conjugate \(-i\pi - 2k\pi i\) :\[z = \frac{1 \times (-i\pi - 2k\pi i)}{(i\pi + 2k\pi i)(-i\pi - 2k\pi i)} = \frac{-i\pi - 2k\pi i}{((-i\pi)^2 - (2k\pi i)^2)}\]Simplify further: \[z = \frac{-i\pi - 2k\pi i}{-\pi^2 - 4k^2\pi^2}\]\[z = \frac{i\pi + 2k\pi i}{\pi^2 + 4k^2\pi^2}\]\[z = \frac{i}{\pi (1 + 4k^2)}\]
05

General Solution for \(z\)

Every \(z\) can be written as \(z = \frac{i}{\pi (1 + 4k^2)}\). This solution depends on the integer \(k\), allowing multiple solutions for different values of \(k\).
06

Enumerate Some Specific Solutions

For specific values of \(k\), we find: - For \(k = 0\), \(z = \frac{i}{\pi}\). - For \(k = 1\), \(z = \frac{i}{5\pi}\). - For \(k = -1\), \(z = \frac{i}{5\pi}\). Continue this pattern for other values if needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are numbers that have both a real and an imaginary part. They are usually expressed in the form \( a + bi \), where \( a \) is the real component, and \( bi \) is the imaginary component. In this expression, \( i \) represents the imaginary unit, which satisfies \( i^2 = -1 \).

A complex number is crucial for calculations involving two-dimensional quantities. This attribute makes them vital in engineering, physics, and even in everyday mathematics. They are particularly useful when solving polynomials that have no real roots.
  • **Real Part**: The real part contributes the position along the x-axis (horizontal) in the complex plane.
  • **Imaginary Part**: The imaginary part gives the position along the y-axis (vertical).

Complex numbers can be easily added, subtracted, multiplied, and divided, following arithmetic rules alongside unique transformations due to the imaginary unit.
Exponential Form
The exponential form of a complex number is a powerful way to express complex numbers, especially for multiplication and division. It leverages Euler's formula, which is represented as \( e^{i\theta} = \cos(\theta) + i\sin(\theta) \). In this form, the complex number is expressed using an angle \( \theta \) and a radius.

This method is efficient in solving problems that might involve trigonometric manipulation. Converting a number to its exponential form simplifies many mathematical calculations. For instance:
  • A complex number \( z \) can be expressed as \( re^{i\theta} \), where \( r \) is the modulus (or magnitude), and \( \theta \) is the argument (or angle).
  • The modulus \( r \) is calculated as \( \sqrt{a^2 + b^2} \).
  • The argument \( \theta \) is found from \( \tan^{-1}(b/a) \).

In our exercise, translating \(-1\) to \(e^{i\pi + 2k\pi i}\) unveils its exponential nature, making it easier to equate and solve with \( e^{1/z} \).
General Solution
Finding a general solution in complex analysis means determining a formula that encompasses all possible solutions to a given equation. For the problem \( e^{1/z} = -1 \), we recognized that various values of \( z \) satisfy this equation depending on the integer parameter \( k \).

By working through the transformation and manipulation of the given complex function:
  • We equate \( 1/z \) to exponential form, i.e., \( 1/z = i\pi + 2k\pi i \).
  • Take the reciprocal of \( 1/z \), then simplify using complex conjugate methods to arrive at \( z \).
  • Simplifying results in the formula \( z = \frac{i}{\pi (1 + 4k^2)} \).

This expression represents the general solution, with each value of \( k \) providing a unique result for \( z \), corresponding to different points on the complex plane. This approach permits comprehensive enumeration for particular solutions by substituting specific integers for \( k \). For instance, \( k = 0 \) yields \( z = \frac{i}{\pi} \), showcasing how easily we can alter solutions.

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